I can't figure out how to show the correct diagram for this earliest deadline first algorithm. So far here is my code:
import java.util.*;
 
 
    class deadlineprototype
    {
 
 
    public static void main(String args[])
    {
 
 
    Scanner sc = new Scanner(System.in);
 
 
    System.out.println("enter no. of processes : ");
    int n=sc.nextInt();
    int job[]=new int[n+1];
    int burst[]=new int[n+1];
    int newburst[]=new int[n+1];
    int arrival[]=new int[n+1];
    int deadline[]=new int[n+1];
    int wt[]=new int[n+1];
    int turn[]=new int[n+1];
    int tot_turn=0;
    int tot_wait=0;
    float avg_turn=0;
    float avg_wait=0;
    int j;
 
    for(int m=1;m<=n;m++)
        {
        arrival[m]=m;
        }
    for(int m=1;m<=n;m++)
        {
        job[m]=m;
        }
 
    for(int m=1;m<=n;m++)
        {
        System.out.println("enter arrival time, burst time and deadline of process "+(m)+"(0 for none):");
        arrival[m]=sc.nextInt();
        burst[m]=sc.nextInt();
        deadline[m]=sc.nextInt();
 
    if (deadline[m]==0){
        deadline[m]=1000;
    }
        }
 
 
 
    int temp;
    for(int i=1;i<n;i++)
        {
        for(j=1;j<n;j++)
            {
 
                if(deadline[i+1]<deadline[j])
                {
                temp=deadline[j+1];
                deadline[j+1]=deadline[j];
                deadline[j]=temp;
 
                temp=job[j+1];
                job[j+1]=job[j];
                job[j]=temp;
 
                temp=burst[j+1];
                burst[j+1]=burst[j];
                burst[j]=temp;
                }
        }
        }
    turn[1]=burst[1];    
 
    for(int i=2;i<=n;i++)
        {
        turn[i]=burst[i]+turn[i-1];
        wt[i]=turn[i]-burst[i];
        }
    for(int i=1;i<=n;i++)
        {
        tot_turn+=(wt[i]+burst[i])-arrival[i];
        avg_turn=(float)tot_turn/n;
        tot_wait+=wt[i]-arrival[i];
        avg_wait=(float)tot_wait/n;
        }
    System.out.println("----------Earliest Deadline Scheduling Diagram----------");
    for(int m=1;m<=n;m++)
        {
    if(deadline[m]==1000){
            deadline[m]=0;
            }
    if(wt[m]==0){
            System.out.println("0"+wt[m]+" _____"); 
    }
    else{
    System.out.println(wt[m]+" _____"); 
    }
            System.out.println("  |     |");
 
            System.out.println("  |job "+job[m]+"|");
 
            System.out.println("  |_____|");
                    try
                 {
                 //newburst[m]=(burst[m]*1000);
                 Thread.sleep(1000);  
                 }catch (InterruptedException ie)
                 {
                 System.out.println(ie.getMessage());
                 }
    }
    System.out.println((wt[wt.length-1]+burst[burst.length-1]));

If I input 2 processes this will be the output:
enter no. of processes : 
    2
    enter arrival time, burst time and deadline of process 1(0 for none):
    0 17 0
    enter arrival time, burst time and deadline of process 2(0 for none):
    0 13 10
    ----------Earliest Deadline Scheduling Diagram----------
    00 _____
      |     |
      |job 2|
      |_____|
    13 _____
      |     |
      |job 1|
      |_____|
    30

It shows the correct intended output. But for 3 processes like this then it will output:
enter no. of processes : 
    3
    enter arrival time, burst time and deadline of process 1(0 for none):
    0 17 0
    enter arrival time, burst time and deadline of process 2(0 for none):
    0 13 10
    enter arrival time, burst time and deadline of process 3(0 for none):
    25 14 20
    ----------Earliest Deadline Scheduling Diagram----------
    00 _____
      |     |
      |job 2|
      |_____|
    13 _____
      |     |
      |job 3|
      |_____|
    27 _____
      |     |
      |job 1|
      |_____|
    44
It shows an incorrect output, that job 1 should come after job 2 and instead of job 3. But then again if I input 5 process it will show correct output again:
enter no. of processes : 
    5
    enter arrival time, burst time and deadline of process 1(0 for none):
    0 17 0
    enter arrival time, burst time and deadline of process 2(0 for none):
    0 13 10
    enter arrival time, burst time and deadline of process 3(0 for none):
    25 14 20
    enter arrival time, burst time and deadline of process 4(0 for none):
    25 10 15
    enter arrival time, burst time and deadline of process 5(0 for none):
    30 5 0
    ----------Earliest Deadline Scheduling Diagram----------
    00 _____
      |     |
      |job 2|
      |_____|
    13 _____
      |     |
      |job 1|
      |_____|
    30 _____
      |     |
      |job 4|
      |_____|
    40 _____
      |     |
      |job 3|
      |_____|
    54 _____
      |     |
      |job 5|
      |_____|
    59
And now I wonder what codes is causing the program to show incorrect input. Please help with this problem thanks in advance!