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Thread: How can I rotate every n elements in an Array list by 1 index?

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    Lightbulb How can I rotate every n elements in an Array list by 1 index?

    Hey guys! I'm still a bit new to Java and I'm working on a problem where I'm supposed to rotate every n elements in an ArrayList.
    The method takes in as parameters: List<Integers> list and an integer n.

    if n = 3;
    If the List contains -> [0,1,2,3,4,5,6,7,8,9,10]
    After the call on rotateEveryN the list should be -> [2,0,1,5,3,4,8,6,7,9,10]

    I know how to go about storing the nth element in a temp variable. And how to move elements
    around. But I seem to be getting confused on how to properly rotate this subset of elements within the list.

    public static void rotateEveryN(List<Integer> list, int n) {
           for (int i = 0; i < list.size(); i++){
               for (int j = i; j <= n; j++){       // <- I know this is where my confusion is starting
                                                             //  How can I only work on three elements at a time from within the list?
                                                             // Should the inner loop be starting back at 0 every n element?                                                
     
               }
           }
        }

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    Default Re: How can I rotate every n elements in an Array list by 1 index?

    how to properly rotate this subset of elements
    Do you have a list of the steps the program must take to solve the problem? A design.
    If not, work on making a list of the steps and post it before trying to write any code.
    You need a design BEFORE trying to write the code.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: How can I rotate every n elements in an Array list by 1 index?

    You were so right. As soon as I stopped and did a little thinking. I realized that the inner loop was unnecessary if I properly incremented the first loop.
    Once I did that the rest seemed to fall right into place!
     int remainder = list.size() % n;
            for (int i = 0; i < list.size() - remainder; i+=n){
                int temp = list.get(i + n - 1);
                list.remove(i + n - 1);
                list.add(i, temp);
            }
     
     
        }

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    Default Re: How can I rotate every n elements in an Array list by 1 index?

    You don't need to call the get method. The remove method returns the removed object.
    If you don't understand my answer, don't ignore it, ask a question.

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