Thread: Arrays (address book)

I am trying to use an if statement in a do while. I have placed a menu inside the do while and then want to use the if statment to deal with the four menu options. The first menu option is to enter Name: Age: and Hometown:. The problem I have is that I want to take the input from the user but the if statement is only printing out the Name: etc and not allowing for user input. I feel like I can't move forward so any help is really really appreciated. As i'm learning at mo and I am really stuck.

Hiya I dont know what code wrapping is, sorry I'm really new to this. Appreciate the help.
Here is my code

import java.util.Scanner;
import java.util.ArrayList;

public class addressbook1
{
public static void main (String args[])
{
Scanner scan = new Scanner(System.in);
String [] Name= new String[100];
int [] Age = new int[100];
String [] Hometown =new String[100];
int index = 0;
int option = 0 ;
String search = "";
boolean end = false;


do {
index ++;
System.out.println("======MENU======");
System.out.println("1: NEW Record Add. ");
System.out.println ("2: SEARCH Record by Name. ");
System.out.println("3: PRINT All Records. ");
System.out.println("4: EXIT ");
System.out.println("What is your option (1-4)? ");
option = scan.nextInt();


if (option == 1)
{ System.out.println("You selected option 1");
System.out.println("--- Adding a Record --- ");

System.out.println("Name: ");
Name[index] = scan.nextLine();

System.out.println("Age " + index + ": ");
Age [index] = scan.nextInt();

System.out.println("Hometown " + index + ": ");
Hometown [index] = scan.nextLine();

}
else if(option == 2)
{
System.out.println("You selected to search for a Record. ");
}
else if (option == 3)
{
System.out.println("You chose Print ALL Records ");
}
else if (option == 4)
{
System.out.println("EXIT");
}
else
{
end = true;
System.out.println("Program has now ended!");
}



}while (end == false);

}
}

--- Update ---

Still working on the first part as you can see I cannot get the program to take input for each variable and print it to screen