read a file word by word

**poornima2806** · February 23rd, 2012, 12:07 AM

Hi all,
I want read a xsl file and produce another xsl file with some tag replaced in it.I have tried with substring but it is not efficient that much,so i thought to read the file word by word.can anyone help me how to do it.i have given below the xsl
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns

sl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="mainpara">
<html>
<xsl:apply-templates/>
</html>
</xsl:template>

<xsl:template match="epigraph">
<div>
<xsl:apply-templates/>
</div>
</xsl:template>

<xsl:template match="para">
<p>
<xsl:apply-templates/>
</p>
</xsl:template>

<xsl:template match="blockquote">
<b>
<xsl:apply-templates/>
</b>
</xsl:template></xsl:stylesheet>
in this i need to replace a epigraph to html and html to epigraph and same like tat for other tags also.

**kenster421** · February 23rd, 2012, 03:14 PM

You should read the entire file into a String and use the replace method for strings.
String (Java Platform SE 6)
Note that since you want to switch tags around you will need to create a temporary tag to change to and revert back

ex: replace <b> with <i>

//opening tags
fileContents.replaceAll("<b>","<@@>");
fileContents.replaceAll("<i>","<b>");
fileContents.replaceAll("<@@>","<i>");
 
//closing tags
fileContents.replaceAll("</b>","<@@>");
fileContents.replaceAll("</i>","</b>");
fileContents.replaceAll("<@@>","</i>");

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