Thread: Java recursive calls

I'm having a little bit of confusion on how recursive calls work.
What does the method call recur2(5) display with the following code?:

public static void recur2 (int n)
{
  if(n<=0)
  { 
    return;
  }
  else
  {
    recur2(n - 2);
    System.out.print(n);
  }
}

I would think it would print "31" but that's not right?

Follow it through. The first call (n == 5) calls itself with 3 but 5 is pushed to be printed later. Then the call is passed 3, it is called with 1 but 3 is pushed to be printed later. Lastly, it is called with 1 which is less than zero and that stops the recursion but the print() is called with 1. So 135 is printed as 1 is that most recent call and on up the stack.