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scope of a class created as local variable
My question is.Will the temp variable will be set to null,so it is going to be de-allocated after the termination of the function?
NothingHere is a class.voidPositionList is a list.
private final void initVoidPositions() { NothingHere temp = new NothingHere("Road"); voidPositionList.add(temp); }
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Re: scope of a class created as local variable
The variable: temp will disappear when the method exits.
The object that temp refers to has a reference saved in the list and will continue to exist and be accessible.
If you don't understand my answer, don't ignore it, ask a question.
Re: scope of a class created as local variable
Thank you very much.If no reference exists to the object,then it is going to be removed by garbage collector.
Re: scope of a class created as local variable
Yes, that's how its supposed to work.
If you don't understand my answer, don't ignore it, ask a question.
Re: scope of a class created as local variable
Thank you very much for you laconic answers.
Re: scope of a class created as local variable
Norm (#4) is right. But I don't think any promise is made about when memory will be freed. Or whether it will be freed this side of your program's termination.Originally Posted by Samaras
The point is that a reference to the object does exist as one of the things in the list, so the newly created NothingHere instance is quite "safe".
Re: scope of a class created as local variable
Yes,i agree with you too
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