Thread: Order of printing

Originally Posted by Bhawani

The output will be :
x c g
First the static block will print, then the constructor, and finally the go() will print

Hi guys, just thought I would jump in here to see if I can get some help with this same question. I understand that the static will print first, and the go() will print last, but what I am really confused on is why the c and the y print in the order they do. They are listed in the following order:
{System.out.print ("c ");}
{System.out.print ("y ");}
but it goes to the second instruction first, hence resulting in the x, y, c, g output.

I have tried adding additional instructions as follows:
{System.out.print ("c ");}
{System.out.print ("y ");}
{System.out.print ("w ");}
{System.out.print ("z ");}
and in every case when it reaches this point, it jumps to the second line first to print whatever is there, follows on with the subsequent lines, only then returning to print the content of the first line before finishing the sequence with the go(). In this example, the output I get is x, y, w, z, c, g.

I can't understand it and I would really appreciate some help as I have tried to get to grips with it by manipulating the program a dozen ways. I am completely new to Java so go easy on me please! What am I missing/not seeing?

Thank you in advance!

Ah Norm - would you believe I just figured it out.
The closing brackets on the initialiser blocks were catching me out. Once you close the first set of brackets, thats the only code that gets passed into the constructor. The next one is just part of the class. So it prints static output, class output, constructor output, method output....
Got it!