Question on how this works?

**sammythesp3rmy** · December 8th, 2013, 04:10 PM

public static void mystery(int num)
{
 if (num > 0)
 {
 mystery(num – 1);
 System.out.print(num + " ");
 }
}
 
mystery(4);
System.out.println();

I was looking through my older notes from a class I took a few years ago, and it was saying the answer was 1 2 3 4 is what outputted when this is run. I would think it is 4 3 2 1, and I don't understand how it is the other way around. Would anyone be kind enough to explain what actually happens to make it 1 2 3 4? Thank you.

**andbin** · December 8th, 2013, 05:11 PM

Originally Posted by sammythesp3rmy

Would anyone be kind enough to explain what actually happens to make it 1 2 3 4? Thank you.

The print is after the recursive invocation of mystery. The last deepest invocation is with 0 but since there is the condition num>0, no recursion and no print happens. Then gets one step back, where the invocation was with 1 and print it ... and go back where was 2 .....

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