Thread: Query about Use of nextLine() method of Scanner class

My code is as follows:

import java.util.Scanner;
public class GetUserInput {
public static void main (String args[]) {
int i;
float f ;
String s;

Scanner input = new Scanner (System.in);



System.out.println ("enter an integer: ");
i = input.nextInt();
System.out.println ("you entered an integer equal to " + i);

System.out.println ("enter a floating point number: ");
f = input.nextFloat();
System.out.println ("You entered a floating point number equal to " + f );

System.out.println ("enter a sentence: ");
s = input.nextLine();
System.out.println ("You entered a sentence which is \" " +s+ " \" ");

}
}


Output:

D:\Java Codebase>javac GetUserInput.java

D:\Java Codebase>java GetUserInput
enter an integer:
2
you entered an integer equal to 2
enter a floating point number:
7
You entered a floating point number equal to 7.0
enter a sentence:
You entered a sentence which is " "



My Query is: input.nextLine() does not wait for user input. Instead it continues execution from next line. But if I move up input.nextLine(); before both input.nextInt(); and input.nextFloat() in the above code, the execution works fine, input.nextLine(); waits for user input. edited code and output are as follows.

import java.util.Scanner;
public class GetUserInput {
public static void main (String args[]) {
int i;
float f ;
String s;

Scanner input = new Scanner (System.in);

System.out.println ("enter a sentence: ");
s = input.nextLine();
System.out.println ("You entered a sentence which is \" " +s+ " \" ");

System.out.println ("enter an integer: ");
i = input.nextInt();
System.out.println ("you entered an integer equal to " + i);

System.out.println ("enter a floating point number: ");
f = input.nextFloat();
System.out.println ("You entered a floating point number equal to " + f );

}
}


output:

D:\Java Codebase>javac GetUserInput.java

D:\Java Codebase>java GetUserInput
enter a sentence:
hi
You entered a sentence which is " hi "
enter an integer:
1
you entered an integer equal to 1
enter a floating point number:
8
You entered a floating point number equal to 8.0


Clarifications Invited.

Thanks in advance,
Satya

When you enter a numeric value and use nextInt() you have entered an Integer and carriage return. nextInt reads the integer and the CR is still in the buffer. Now you call nextLine which reads the old CR form the buffer. Your first class will work if you insert input.next() before reading the sentence.