Thread: If statement help

I am trying to write an if statement based on input from a String that is dependant on the input from the user.

import java.util.Scanner;
 
public class FirstProject {
	public static void main(String [] args){
		Scanner input = new Scanner(System.in);
 
		System.out.println ("Please tell me your name.");
		String name = input.nextLine();
		System.out.println ("Hello " + name + "!");
 
		if (name = Ryan){
			System.out.println ("Do the following please.");}
		else{
			System.out.println ("Please come back later.");}
	}
}

As you can see I am trying to write an "if " statement based on the output for the "String name". Being that this entry is dependent on input from the user I can't specify in my "if" statement a static entry (name = Ryan) to continue. How would I go about doing this?

if(name.equalsIgnoreCase("Ryan"))

Thank you. This did resolve the issue but now I have another issue. I just just ran the program after adding the valid "if" identified above and it for some reason is printing out the "else" statement as well. I have pasted the results below. I though if the argument was satisfied in the "if" statement then the "else" was ignore but that doesn't seem to be the case. The only think that I have done differently is added an additional "if" statement prior to the "else" statement.

import java.util.Scanner;
 
public class FirstProject {
	public static void main(String [] args){
		Scanner input = new Scanner(System.in);
 
		System.out.println ("Please tell me your name.");
		String name = input.nextLine();
		System.out.println ("Hello " + name + ("!"));
 
		if (name.equalsIgnoreCase ("Ryan"))
			{System.out.println ("Do the following.");}
		if (name.equalsIgnoreCase ("Sarah"))
			{System.out.println ("Do this.");}
		else
			{System.out.println ("Please come back later.");}
	}}

Please tell me your name.
Ryan
Hello Ryan!
Do the following.
Please come back later.

I think you have to read more tutorials about statements
use else if statement instead of second if

The if-then and if-then-else Statements (The Java™ Tutorials > Learning the Java Language > Language Basics)

im pretty new to java but i have been doing these for a while now so im getting good

the way you have it right now is if if else so when you run it and the name ryan comes in it says *if ryan do this* so it does. then since you have another if statement right after it starts an *if sarah do this else do that* and since ryan was entered it wasnt sarah so it moved to the else...should be *if ryan do this else if sarah do this else do this...then its all 1 statement instead of 2

i hope that all made some sense

Thank you everyone for your support. I found that tutorial that Sean4u posted as very helpful. I think I am sure I will figure it out from here and will re-post if I run into any other issues.

In if condition you are using "=" it means that you are assinging value of name to Ryan. In this statment condition is not cheking. Change to "==" this is operator which is used to chek the values.

You should never compare two Strings with "==". Always with <object>.equals(<other>) or variations on it.

Your problem is that you're testing for two conditions that should have been related:
if (x) a
if (y) b
else c

Obviously, because "x" will fail the 2nd if, it will go on the else branch and do "c"
The proper version should have been:
if (x) a
else if (y) b
else c

public static void main(String [] args){
Scanner input = new Scanner(System.in);

System.out.println ("Please tell me your name.");
String name = input.nextLine();
System.out.println ("Hello " + name + "!");

if (name =="Ryan"){
System.out.println ("Do the following please.");}
else{
System.out.println ("Please come back later.");}
}

Hi,


You have written
if (name.equalsIgnoreCase ("Ryan"))
{System.out.println ("Do the following.");}
if (name.equalsIgnoreCase ("Sarah"))
{System.out.println ("Do this.");}
else
{System.out.println ("Please come back later.");}

The 2 if statements are different and only one else you have written, that to second if.Because of this once the first if gets executed and prints the statement with in it as ithe condition satisfied and also it checks the next if, there the conditoin fails and it prints the corresponding else statement.

To avoid this you can write your code as follows :

if (name.equalsIgnoreCase ("Ryan"))
{System.out.println ("Do the following.");}
else if (name.equalsIgnoreCase ("Sarah"))
{System.out.println ("Do this.");}
else
{System.out.println ("Please come back later.");}


Thanks & Regards
Divakara