Thread: Looping through a multidimensional array

Well I made myself a nice MultiDimensional array:

 int[][] newboard = {{0,0,0,0,6,0,0,0,9},
                        {0,6,0,0,0,0,3,0,1},
                        {2,0,0,0,0,9,8,0,0},
                        {1,9,6,0,0,2,0,0,8},
                        {0,0,0,3,0,8,0,0,0},
                        {8,0,0,9,0,0,1,7,5},
                        {0,0,1,7,0,0,0,0,4},
                        {6,0,7,0,0,0,0,8,0},
                        {4,0,0,0,9,0,0,0,0}};

And I need to somehow scan through that board going from left to right, starting at the right side in the next row , printing out the array location of o's in the multidimensional array. This isn't homework, here's what I tried to do, it only prints out the 0's in the first row.

So for the first 0 on the top left in the newboard[][], I need it to return
X = 0;
Y = 0;

Here's what I tried, I'm not quite sure how to get it to read more than the first row;

public void emptycellsearch(){
	int y = 0;
	int x = 0;
	for(x = 0;x<=8;x++){
		for(y = 0;y<=8;y++){
			if(x==0 && newboard[x][y]==0){
				System.out.println("X value is ");
				System.out.println(x);
				System.out.println("Y value is ");
				System.out.println(y);
			}
		}
	}
}

if(x==0 && newboard[x][y]==0)

It will only print out things if x equals zero (first row). Incidentally, I think you meant to do this:

for (int row = 0; row <= 8; row++)
{
     for(int col = 0; col <= 8; col++)
     {
          if (newboard[row][col] == 0)
          {
               //.. print out stuff
          }
     }
}

Rows run left/right, so their indices denote how far up/down they are, and columns run up/down, so their indices denote how far left/right you are (kind of confusing, but that's life).