Thread: (Simple) How to use an if statement to respond to random integers

Hello,

I have a simple question. How do I use an if statement to check and respond to a randomly generated integer? For instance if the number is 4, it would print "Chicken"
but for 5 it would print "Steak" and so on. Is their a simple way to do this?

Thanks.

Well first you have to generate a random number, which can be done in the Random class, then you simply compare the int it returns with either a switch statement or if statement.

The switch Statement (The Java™ Tutorials > Learning the Java Language > Language Basics)

Originally Posted by DusteroftheCentury

Hello,

I have a simple question. How do I use an if statement to check and respond to a randomly generated integer? For instance if the number is 4, it would print "Chicken"
but for 5 it would print "Steak" and so on. Is their a simple way to do this?

Thanks.

By randomly generated integer, you mean within some range, right? Also, is there any behavior of your program to print a certain statement in particular conditions or it's iterative? Means it will print different String at different Integers?
Well, in any case you must stick to switch and if.

What do you mean by block of code? Are you talking about code with a pair of {} within a method
or do you mean a class?
You need a reference to the component whose methods you want to call.

Post a small piece of code to show what you are trying to do.

Originally Posted by Norm

What do you mean by block of code? Are you talking about code with a pair of {} within a method

^this

Here is the peice of code Im talking about:

public void actionPerformed(ActionEvent e)
{
	if (e.getSource() == button1);
		{
		int low = 1;
		int high = 5;
		int rnd = (int)(Math.random() * (high - low + 1)) + low;
		if (textbox1.getText().equals("Hi"))
		//For all the printlns I would like something like label1.setText("Hello"), while keeping label1 created in the main code for the panel if possible
 
		{
			if (rnd == 1)
			System.out.println("Hello.");
		}	
		{
			if (rnd == 2)
			System.out.println("Greetings!");
		}
		{
			if (rnd == 3)
			System.out.println("Salutations.");
		}
		{
			if (rnd == 4)
			System.out.println("Hey there.");
		}
		{
			if (rnd == 5)
			System.out.println("Whats up?");
		}
		}
	}
}

Thanks for helping,

-Duster

Thanks Norm that worked like a charm!

Also thanks for the definition, I hat not being able to use proper terms.

Thanks so much for the simple explanation!

-Duster

Getting the right vocabulary can be important. There are many terms and techniques in IT with their own names.
You'll be able to ask better questions with the right word.