Thread: Logic of Hangman

I'm working on a project for school and was curious
whether there is a better way to perform some the
logic in my hangman program. It plays like hangman
but you can't lose depending on the number of moves.

import java.util.*;
 
class Hangman {
    static Scanner scan = new Scanner(System.in);
    static Random rand = new Random();
 
    static boolean isIn(char c, String str) {
        int occurrence = str.indexOf(c);
        if (occurrence >= 0)
            return true;
        else
            return false;
    }
 
    static boolean printCurrStatus(String strToGuess, String userInputs) {
        String current = "";
        String positionTemp = "";
        String currentTemp = "";
        for (int i = 0; i < strToGuess.length(); i++) {
            current += "_" + " ";
            positionTemp += strToGuess.charAt(i) + " ";
        }
 
        for (int i = 0; i < userInputs.length(); i++) {
            char input = userInputs.charAt(i);
            if (isIn(input, strToGuess)) {
                int index = 0;
                int position = 0;
                while (index > -1) {
                    index = positionTemp.indexOf(input, position);
                    if (index < 0)
                        break;
                    else {
                        currentTemp = current.substring(0, index) + input;
                        currentTemp += current.substring(index + 1,
                                positionTemp.length() - 1);
                        current = currentTemp;
                        position += 1;
                    }
                }
            }
        }
        System.out.println(current);
 
        if (current.indexOf('_') < 0)
            return true;
        else
            return false;
 
    }
 
    static String getNextWordToGuess() {
 
        String[] nextWord = { "elephant", "tiger", "monkey", "baboon",
                "barbeque", "giraffe", "simple", "zebra", "porcupine",
                "aardvark" };
        int newRandom = rand.nextInt(nextWord.length);
 
        return nextWord[newRandom];
 
    }
 
    static void playGame() {
        String userInput = "";
        String wordToGuess = getNextWordToGuess();
        while (!printCurrStatus(wordToGuess, userInput))
        {
            System.out.println("Enter next letter:");
            userInput += scan.next();
        }
 
 
    }
 
    public static void main(String[] args) {
        String choice = "y";
        while (choice.equals("y")) {
            playGame();
            System.out.println("Do you want to play again?  (y or n)");
            choice = scan.next();
        }
        System.out.println("Thanks for playing!");
    }
}

Everything works fine but I'm curious on whether there
is a way to simplify the printCurrStatus method. I do not
want to change this method into multiple methods.

I'm new to the site and appreciate your time. I hope to
be a contributor soon.