Thread: Getting ArrayIndexOutBound Exception

while(chararr[i]!='\0'){

What might happen if the string does not contain the '\0' character? In fact, does the string contain the '\0' character? Are you coming from a C++ background (String's in java are not null terminated)?

Then how we can find once we come to end of the string in java.Becuase here we can not use normal string lenght() method.

Why can't you use the String length() method? You can also access the length of the returned char array using the build in length property of the array. (See
Arrays (The Java™ Tutorials > Learning the Java Language > Language Basics) )

Originally Posted by nike

Yes I am from C++ background.

So as String in java is not Null terminated.Then how we can find once we come to end of the string in java.Becuase here we can not use normal string lenght() method.

Since the exercise is to not use String methods for getting the length, and we already have an array of chars, we can let the array tell us when it's done using for-each loops:

public class StringLengthwithoutMethod {
 
  public static void main(String[] args) {
 
    String str = "This is string";
    int i = 0;
    char[] chararr = str.toCharArray();
 
    System.out.print("Gimme a");
    for (char c : chararr) {
      System.out.print(" \"" + c + "\"! ");
      i++;
    }
 
    System.out.println("\nString length: " + i);
  }
}

There are a few more ways one could skin this String.