Thread: For loop not executing as expected - Very simple coding

 
for (int i=0; i<=5; i++) {
     System.out.println("Outer for loop: i = " + i);

i is 4 after it breaks out of the while loop and before it re-enters the above for loop. Since 4 <= 5, I thought the next line of code "System.out.println("Outer for loop: i = " + i)" would be executed before i++ in the code "for (int=0; i<=5; i++)" was iterrated?

My understanding is for loops work in the following way:

for (statement 1; statement 2; statement 3) {

The code block to be executed would appear here

}

Statement 1 is executed only one time: It is executed before Statement 2 or Statement 3 are executed and before the code block is executed – the code block is only executed if Statement 2 evaluates to true. Statement 1 simply sets a variable before the loop starts.

Statement 2 defines the criteria which determines if the code block will be executed. If the criteria is met, the code block is executed before Statement 3 is executed. If the criteria is not met, the code block is not executed.

Statement 3 is executed after the code block is executed.

Consequently, my understanding is after the code breaks out of the while loop i = 4 and the following should occur:

[code=Java]

for (int i=0; i<=5; i++) {
System.out.println("Outer for loop: i = " + i);

[\code]

4<=5 is true. Therefore, the code block would be executed BEFORE i is iterated again. This would print: Outer for loop: i = 4.
After the code block is executed, i would then be iterated and equal 5.

5<=5 is true. Therefore, the code block would be executed BEFORE i is iterated again. This would print: Outer for loop: i = 5.
After the code block is executed, i would then be iterated and equal 6.

6<=5 is false causing the code to exit the program.

My understanding of how this code should work is as follows:

After i is iterated to 4 at the bottom of the inner while loop, it then evaluates statement 2 of the inner while loop. Since 4<=3 is false, it then exits the inner while loop and returns control back to the outer for loop.

i = 4 as it now enters the for loop for the second time. It then evaluates statement 2 of the outer for loop. Since 4<=5 is true, it then should execute any statements within the curly braces/code block. Therefore, it should print: Outer for loop: i = 4.

AFTER the for code block(s) are completed then it iterates to 5 and evaluates statement 2 of the outer for loop for a third time. Since 5<=5 is true, it then executes any statements within the curly braces/code block. Therefore, it prints: Outer for loop: i = 5.

Are you telling me when i enters the for loop it is 4 but as soon as it determines 4>=5 it then iterates to 5 - BEFORE performing any other evaluations/actions?

Thank you! Thank you! Thank you! I knew that but had forgotten after going through the while statement that it had never iterated the first time. I was concentrating on the inner while loop so much that I forgot.

You have made my night! Thanks!