Thread: Creation of lotto type program

alright, this is the last bit of help i need for the program, we have been asked to create a lotto type program, since i finished early i've decided to add some error checkers. one being that you cannot enter the same number twice.

package lotto;
import java.util.*;
public class Main {
    public static void main(String[] args) {
        int totalcount = 0;
        say("Welcome to The lotto!");
        int[] userinput;// declaring a new array of chars
        userinput = new int[6];//allocating 6 slots for memory
    [COLOR="Red"]    for (int array = 0; array < 6; ++array) {
            userinput[array] = finduserinput();
        }[/COLOR]
        int[] Computernumber;
        Computernumber = new int[6];
        for (int array2 = 0; array2 < 6; ++array2) {
            int tempstore = findcomputernumber();
            for(int loop = 0; loop < 6;++loop){
               if(tempstore == Computernumber[loop] ) {
                   tempstore = findcomputernumber();
               }
               else{
 
               }
            }
            Computernumber[array2] = tempstore;
            say("Random number is : " +Computernumber[array2]);
 
        }
        for (int count = 0; count < 6; ++count){
            for(int count2 = 0; count2 < 6; ++count2){
                if(userinput[count] == Computernumber[count2]){
                    totalcount = (totalcount + 1);
                }
            }
        }
        say("you had "+totalcount+" matches");
if(totalcount < 3){
    say("You have won nothing.");
}if(totalcount > 4){
    say("You have won one million dollars!");
}else{
            int randomwin = findrandomwin();
}
 
    }
    public static void say(String aMessage) {
        System.out.println(aMessage);
    }
    [COLOR="Red"]public static int finduserinput() {
        int name = 1;
        say("please choose a number between 0 and 40");
        try {
            Scanner scan1 = new Scanner(System.in);
            name = scan1.nextInt();
        } catch (InputMismatchException ime) {
            say("There was an error in your typing please make sure the value entered is within the set parametres");
            finduserinput();
        }
        if (name > -1 && name < 41) {
        } else {
            say("That was not a valid number please check your number and try again");
            finduserinput();
        }
        return name;
    }[/COLOR]
    public static int findcomputernumber() {
        Random Rndnumber = new Random();
        int RandomNum = Rndnumber.nextInt(41);
        return RandomNum;
    }
    public static int findrandomwin(){
        Random Rnd = new Random();
        int Randomwin = Rnd.nextInt(101);
        return Randomwin;
    }
}

the area's highlighted are the area's where the code will be inserted i think.. i'm not asking for the exact code needed, but rather an example or hint as to what i will need to do.

cheers,
luke.

hey mate, i think i see what you're doing there. could you please explain this to me; Arrays.fill(userinput, -1);
thanks.
cheers,
luke.

understand perfectly, i will not mark this thread as solved though as i plan to ask another question on it later tonight.

cheers,
luke.

alright, very last bit of it.

package lotto;

import java.util.*;

public class Main {

public static int[] userinput = new int[6];// declaring a new array of chars
public static int[] Computernumber = new int[6];

public static void main(String[] args) {
int money = 40;
int totalcount = 0;
int repeat = 0;
for (; repeat == 0 {
Arrays.fill(userinput, 0);
Arrays.fill(Computernumber, 0);
say("Welcome to The lotto! each game will cost you 5 fun coupons");


for (int array = 0; array < 6; ++array) {
userinput[array] = finduserinput();


}

for (int array2 = 0; array2 < 6; ++array2) {
Computernumber[array2] = findcomputernumber();
say("Random number is : " + Computernumber[array2]);

}
for (int count = 0; count < 6; ++count) {
for (int count2 = 0; count2 < 6; ++count2) {
if (userinput[count] == Computernumber[count2]) {
totalcount = (totalcount + 1);
}
}
}
say("you had " + totalcount + " matches");
if (totalcount < 3) {
say("You have won nothing.");
}
if (totalcount > 4) {
say("You have won one million dollars!");
money = (money + 1000000);
} else {
int randomwin = findrandomwin();
money = (money + randomwin);
}
repeat = askrepeat();
}
}

public static void say(String aMessage) {
System.out.println(aMessage);
}

public static int finduserinput() {
int name = 1;
say("please choose a number between 1 and 40");
try {
Scanner scan1 = new Scanner(System.in);
name = scan1.nextInt();
} catch (InputMismatchException ime) {
say("There was an error in your typing please make sure the value entered is within the set parametres");
finduserinput();
}
if (name > 0 && name < 41) {
} else {
say("That was not a valid number please check your number and try again");
finduserinput();
}
for (int array = 0; array < 6; ++array) {
if (userinput[array] == name) {
say("You cannot repeat your number input please enter another number.");
finduserinput();
} else {
}
}
return name;
}

public static int findcomputernumber() {
Random Rndnumber = new Random();
int RandomNum = Rndnumber.nextInt(7);
for (int array = 0; array < 6; ++array){
if(RandomNum == Computernumber[array]){


findcomputernumber();
}

}
return RandomNum;
}

public static int findrandomwin() {
Random Rnd = new Random();
int Randomwin = Rnd.nextInt(101);
return Randomwin;
}

public static int askrepeat() {
say("you have " + "Fun coupons left would you like to play again?");
int answer = 0;
try {
answer = System.in.read();
System.in.read();
} catch (Exception e) {
say("Error in input");
askrepeat();

}
if (answer == 89 || answer == 121) {
answer = 0;
} else if (answer == 78 || answer == 110) {
answer = 1;
}
return answer;
}
}

i tried to replicate what you have done, in making sure that the same number is not generated by the computer, but it seemed to fail. i still got this output.

Random number is : 0
Random number is : 2
Random number is : 5
Random number is : 3
Random number is : 3
Random number is : 3

any help??


cheers,
luke.