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Thread: Collatz conjecture

  1. October 27th, 2010, 07:00 AM #1
    Ripcurl
    Ripcurl is offline
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    Default Collatz conjecture

    ok, so I am building a program that calculates a number that user enter, with the collatz conjecture principles.

    A random number is entered, if it is an even number it shall be divided by 2,if it is an odd number it must be multiplied by 3 + 1 and then divided by 2.. This goes in a loop until the number is 1. I have already found the method for this, but I do not get the number to not be negative.

    question is: how do I prevent the number from going over to the negative side?
    First i tried : while(X>1) but that doesent work, so I thought while(X!=1) but that doesent work either. And when i enter the number 837799 the computer goes in to a endless loop..

    I DONT WANT THE COMPLETE ANSWER, just a nod in the right direction!
    Last edited by Ripcurl; October 27th, 2010 at 07:26 AM. Reason: EDIT: Never mind, figuerd it out! :D
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