Thread: Using a For loop for repetition

Actually, as long as the condition is true the for loop will keep running. This can lead to some very interesting for-loops.

for (int i = 5; i >= 0; --i) // a for loop which counts down
{}
int count = 0;
for (int i = 0; count != 128; ++i) // a for loop which tests for a different number exactly equaling a number
{}
 
for(int i = 0;; ++i) // Java will automatically assume a true condition. This is an infinite for-loop

I would personally do something like this:

import java.util.*;
 
public class WashingMachine {
 
	/**
	 * JavaProgrammingForums.com
	 */
	public static void main(String[] args) {
 
		System.out.println("Washing Machines(1) Stove(2)");
		Scanner input = new Scanner(System.in);
		int choice;
 
		while(input.hasNext()){
 
			choice = input.nextInt();
 
			if(choice == 0){
				break;
			}
			if(choice == 1){
				System.out.println("Washing Machines");
			}
			if(choice == 2){
				System.out.println("Stoves");
			}		
 
		}		
 
	}
}

The 'while loop' will continue to loop until 0 is entered.

Normally, I would discourage the use of break/continue statements used for something that could easily be fixed by changing the conditions. The reason is these statements (especially breaking to a label) encourage "spaghetti code", or code that's difficult to follow the logic of. While break/continue statements aren't anywhere near as bad as goto statements, they're still something you may want to avoid if possible. There are a few key exceptions to this rule (obviously having break statements in switches is almost always a must).

In this case, this problem could be fixed by using a "1 and a half" while loop, or a do-while loop.

// the do-while loop solution
do
{
    System.out.println("Washing Machines(1) Stove(2)");
    choice = input.nextInt();
    if(choice == 1){
				System.out.println("Washing Machines");
			}
			if(choice == 2){
				System.out.println("Stoves");
			}	
}
while(input.hasNext() && choice != 0);