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Thread: User Input Loop

  1. #1
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    Default User Input Loop

    I've been messing around with this for a bit and cannot seem to code it so that it will work as intended. I'm trying to prompt the user for input repeatedly, until the user enters a -1, when the loop is supposed to terminate.

    My problem lies in that the loop does not stop when -1 is entered. What am I doing wrong here?

    import java.util.Scanner;
     
    class Test{
     
    public static void main(String[] args){
        Scanner scan = new Scanner(System.in);
        String in = scan.nextLine();
     
        while(in != "-1"){
          System.out.println("You entered: " + in);
          in = scan.nextLine();
     
        if(in == "-1")
          System.out.println("Stopped");
          break;
       }
      }
     }
    Last edited by cfmonster; August 17th, 2009 at 12:30 PM.


  2. #2
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    Default Re: User Input Loop

    BTW,

    do in.trim().equals("-1") instead of in == "-1"

    also print and see what it is printing?

    Please note that you are doing redundant check in your while just for entry check.

    probably, you could write:

    if (!in.trim().equals("-1")) {
    while (1) {
    ....// rest code
    if(in.trim().equals("-1"))
    System.out.println("Stopped");
    break;
    }
    }
    }
    Acumen,
    Lucid forums

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    Super Moderator Json's Avatar
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    Default Re: User Input Loop

    Here's another one of my best practise tips, whenever you are doing string comparison on constant strings, always call the equals method on the constant to avoid null pointers.

    if ("-1".equals(input)) {
        // Do some magic!
    }

    // Json

  4. #4
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    Default Re: User Input Loop

    Agreed, I would suggest the same for all cases like

    int i = fun();

    if (-1 == i) {
    // do something
    } else {
    // do something else
    }
    In such case u don't end up doing

    -1 = i, but i = -1 would have messed up things for you

    Acumen,
    Lucid forums

  5. #5
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    Default Re: User Input Loop

    Thanks. I hadn't realized that there was a built in method for string comparison.

  6. #6
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    Default Re: User Input Loop

    while(1) won't work... Java has abstracted that away

    Yes, Java's comparison is different because of the way it creates objects for pretty much everything. Using the == operator only compares the addresses the objects are held at, instead of their actual content.

  7. #7
    Java kindergarten chronoz13's Avatar
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    Default Re: User Input Loop

    so the "-1" will be serve as a character?

  8. #8
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    Default Re: User Input Loop

    Quote Originally Posted by chronoz13 View Post
    so the "-1" will be serve as a character?
    The "-1" in this example is being read as a String.

    Double quotes are for string representation, while single quotes are for character representation.

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