Thread: Hello, I'm new and I need help. . .

I want my program to be able to read an array of integer type and count the frequency of each integer in the array. For example, if my array consist of 10 components = {1,1,2,3,1,2,1,1,5,4}, I need my program to be able to say that there are five 1's, two 2's, one 3, one 4, and one 5. I could only go as far as the first occurring integer, something is wrong with my second outer for loop, I think

Here's my code so far:

import java.util.*;
 
public class Yellow
{
	static Scanner console = new Scanner(System.in);
	public static void main(String[] args)
	{
		int numOfElem;
		System.out.println("Enter how many integers you want to input into the array: ");
		numOfElem = console.nextInt();
		System.out.println();
		int[] list = new int[numOfElem];
	//	int i;
		int freq = 1;
		System.out.println("Enter " + numOfElem + " integers: ");
		for (int i = 0; i < numOfElem; i++)
			list[i] = console.nextInt();
		System.out.println();
 
		for (int i = 0; i < numOfElem; i++)
		{
			System.out.print(list[i] + " ");
			int searchItem = list[i];
			for (i = i + 1; i < numOfElem; i++)
			{
				if (list[i] == searchItem)
					freq++;
				else
					freq = freq;
			}
			System.out.print("   " + freq);
			System.out.println();
		}
		System.out.println();
	}
}

Thanks for any help.

something is wrong with my second outer for loop, I think

For future reference it helps to describe a bit more about what is wrong...for example the input you give and the output you get. That being said, there is an issue with your second loop...mainly it is using the same int variable as the first - once its finished it will go back to the first loop, which then exits (i will be equal to numOfElem). A quick fix is to use a different int variable in the second loop.