Thread: how operator( && or || works).....

int k=5|6|7; how it works ....
int k=4&5&6; how it work .....

it's bit-wise operation: OR | and the other AND &

Originally Posted by Krumpir

Those are used to represent boolean operators. The && is used for AND statements and the || for OR statements.

The expression "A || B" will return true if either A or B where "A && B" will only return true if both A and B are true.

if(true || false)
//code will run
if(false || false)
//code will not run
if(true && false)
//code will not run
if(true && true)
//code will run

Sir, These Things i know .
But my question is different

e.g int k=5&4; give result k=4;

but i fail to decide the result of int k=4&2&6;

the same problem is with OR operator....

Originally Posted by Krumpir

Basic OR logic:
x y x&y
--------------
1 0 | 0
1 1 | 1
0 1 | 0
0 0 | 0

In binary the numbers are represented as follow:
4: 100
2: 010
6: 110

The and operator will only return 1 when all 3 bits are 1.

4: 1 0 0
2: 0 1 0
6: 1 1 0
----------
0 0 0

Thus the value of 4&2&6 is zero.

Using the OR operator if only one bit needs to be 1 in order to return 1;

4: 1 0 0
2: 0 1 0
6: 1 1 0
----------
1 1 0

Thus the value of 4&2&6 is 6.

I hope you understand now, otherwise there is another explanation here: Bitwise operators in java

Thanks ......