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Working with log math function
I want to output to calculate the following:
0 - (3/6)logbase2(3/6) = 1/2
I have this in my program:
double ratio = 3/6; x = x - (ratio * (logbase2(ratio)));
which should equal .5 but I keep getting 0.326634259978281
what am I doing wrong?
Edit: I figure it out. I should be using:
(ratio * Math.log(ratio)/Math.log(2))
Last edited by colerelm; October 15th, 2012 at 06:36 PM.
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