Thread: Java exception "result already defined"

Hello rptech. Welcome to the Java Programming Forums

You are getting this error because you are setting the variable 'result' twice.

You only have to make a very small change:

class Bool {
 
    public static void main(String[] args) {
 
        boolean result = false;
        System.out.println("The boolean is before call " + result);
 
        ChangeBool(result);
        System.out.println("The boolean returned after call to method "
                + result);
    }
 
    public static boolean ChangeBool(boolean result) {
 
        [B]result = true;[/B]
        System.out.println("Change boolean value, result is " + result + " in method");
        return result;
    }
}

No problem rptech,

It was a very small mistake. I'm glad I could help.

Please can you mark this thread as solved. (Check the link in my signature)

Thank you.