Thread: nextint() Method !

hi all

i need help in this exercise :-

develop main method that initializes a random object with the default constructor and then determines the elapsed time for the nextint() method to generate 123456789

-------

how

Define help...what do you have so far? If nothing, start here: The Java™ Tutorials

Originally Posted by copeg

Define help...what do you have so far? If nothing, start here: The Java™ Tutorials

this is my basic idea

 Random r = new Random();
 
 for(int i=1;i<10;i++){
 int Number = r.nextInt(10);
 System.out.println(Number);

this code generate 9 random numbers , now i need to generate 123456789 using this method

anyone help me

ok i trying in this idea :-

Random r = new Random();
for(int i=0;i<9;i++){
     int[] array=new int[9];
 int Number = r.nextInt(10);
 if((Number==1) || (Number==2) || (Number==3)||(Number==4)||(Number==5)||(Number==6)||(Number==7)||(Number==8)||(Number==9))
         Number=array[i];
 System.out.println(array[i]);
    }

the output is :

0
0
0
0
0
0
0
0
0


Why !! why it not working

When equating two values, the left operand is assigned the value of the right. Inspect your code carefully and you will see that the values within the array are never assigned anything (and thus you print their default value of 0)

Cross posted
nextint() Method ! - Java Forums

db

???????????

???????????

!!!!!!!!!!!

Originally Posted by JavaPF

I would do it like this:

import java.util.Random;
 
public class Numbers {
 
	/**
	 * JavaProgrammingForums.com
	 */	
	public static void main(String[] args) {
 
		Random r = new Random();
 
		int Number;
		int Count = 1;
 
		while(Count != 10){
 
			Number = r.nextInt(10)+1;
 
			if(Number == Count){
				System.out.print(Number + " ");
				Count++;
			}						
		}
	}	 
}

Output:

Man !

thanks very much

100%

and i'am understand the idea in true way

Originally Posted by helloworld922

That condition is completely unnecessary. The definition of nextInt() is that it will return an integer in the range [0,10). Simply change your random-number generation statement to this and there's no need for an if statement.

int number = r.nextInt(9) + 1;
// no need for an if statement, number is guaranteed to be in the range [1,10]
array[i] = number;
// ...other code

Yes !

thanks for your useful idea