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BlackJack game rules if both bust
This is not a programming question, but I don't know the rules of BlackJack (card game). My question is, what happens in BlackJack when both player and the dealer goes over 21 (busts by going over)? Do they both fail? Who wins or loses if any? I need to know this to finish a Java project.
Thanks,
Tony
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Re: BlackJack game rules if both bust
They play in sequence. If one busts, the other doesn't play and wins.
If you don't understand my answer, don't ignore it, ask a question.
Re: BlackJack game rules if both bust
So, I always go first, if I go over, the dealer automatically wins even if the dealer is also over?Originally Posted by Norm
Re: BlackJack game rules if both bust
How can the dealer go over if he hasn't taken any cards yet?
All the hands are given 2 cards initially.
Then the first player gets cards until ...
Then the next player
...
finally the dealer
If you don't understand my answer, don't ignore it, ask a question.
tonynsx (November 1st, 2013)
Re: BlackJack game rules if both bust
Ok, thank you.
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