Thread: Need help with classes and constructors!!

Hello everyone, I am new to java and method calls from outside a class is still a little confusing to me, What I am trying to do is take a square object defined in one class and calculate the area and perimeter of that square object inside a different class( probably an easy task for someone with a decent grasp on this topic). I will attach my code that I have so far to make the area so that you can see where I am heading. I'm looking for feedback as to why I can't call the area function from the printSquareMeasurements method.

class Square extends SquareCalc {
 
	private double side;
	public double area;
 
	public Square (Square sq){
 
	side = s;
 
	}
 
	public double Area (Square sq){
 
		area = s * s;
 
		return area;
	}
}
 
public class SquareCalc {
 
static void printSquareMeasures(Square sq){
 
    System.out.println("area = " + sq.Area());
}
 
    public static void main(String[] args) {
 
    	Square sq = new Square(4);
 
    	printSquareMeasures(sq); // call to function that displays results
 
 
    }
}

Originally Posted by KevinWorkman

What you want to do is define a getArea() method in your Square class. It doesn't take a Square parameter, it IS the Square.

Then from your SquareCalc class, you simply create an instance of Square, then call its getArea() method. You shouldn't be using calls to the Square.area variable directly (in fact I don't think you should have an area variable in your Square class at all), but just call that method instead.

Thanks, what you are sayin seems right but I just cant grasp it. I made

public double getArea(double a){
 
	area = a * a;
	return area;
	}

inside class Square, but how can I run that from printSquareMeasures? I tried

System.out.println("This is drivin me insane"+area);

but no luck

Originally Posted by KevinWorkman

You have to call the method, which means you have to have an instance of Square.

Hint: System.out is a variable. When you do System.out.println(), you are really calling the println() method of the System.out variable.

But I already have an instance of Square which is sq right? So it should work if I do sq.getArea(); All I need to do is display the calculation made in getArea...

I ended up revising my code and decided to go with

 
class Square {
 
	public double side;
	public double area;
	public double perim;
 
	public Square (double s){
 
	side = s;
 
	}
 
public double getPerim(double p){
 
	perim = p * 4;
	return perim;
 
}
 
public double getArea(double a){
 
	area = a * a;
	return area;
	}
 
 
 
}
public class SquareCalc {
 
 
static void printSquareMeasures(Square sq){
 
	System.out.println("Area = "+sq.getArea(4));
	System.out.println("Perimeter = "+sq.getPerim(4));
 
}
 
 
 
 
    public static void main(String[] args) {
 
    	Square sq = new Square(4);
 
 
    printSquareMeasures(sq); // call to function that displays results
 
 
    }
}

Originally Posted by KevinWorkman

To quote a professor of mine in college, "Now you're cookin' with gas."

Thank you for all your help tonight I really appreciate it!