Thread: 0 seems to be comming out as 48?

I have writen the following code but for some reason all the numbers seem to be offset by 48?

String bdString;
Vector<Integer> v = new Vector<Integer>();
 
BigDecimal bd = new BigDecimal(Math.pow(2, 1000));
bdString = bd.toString();
 
for (int i = 0; i < bdString.length(); i++) {
	v.add((Integer.valueOf(bdString.charAt(i)).intValue()));
}

When I check the vector all 0's have been entered in as 48, all 1's have been entered in as 49, 2's as 50 etc. I know I'm going to feel like a fool when somebody points it out but... What is going on?

Hi tarkal,

a char is stored as an int, thus when using Integer.valueOf(), you are essentially requesting the value of another interger, in ASCII 48 is the integer number of the character '0'. So you could just subtract 48 from each number, or consider the following method:

Character.getNumericValue()

Chris

Ooooo I like the look of Character.getNumericValue().

Thanks