Thread: Comparing Input to array

Hello, I'm looking for some help on the following program.
The program generally should follow this concept

Create a program name Sequence.java which accepts an integer input from com-
mand line and outputs “found” if the input is found in sequence array and “not
found” otherwise. You need to define sequence to be of type array of int and
statically initialize it as follows:
int[] sequence = { 2,3,4,10,-11,25,31,-21, 14, 18, 131, 99, 721, 23, 44, 802, 820,
-603, 102, 53, 64, -912, 1201, 3001 };

Here is the code i wrote


public static void main(String[] args) {



int[] seq = {2, 3, 4, 10, -11, 25, 31, -21, 14, 18, 131, 99, 721, 23, 44, 802, 820, -603, 102, 53, 64, -912, 1201, 3001};

int input = Integer.parseInt(args[0]);

if (input == seq.length)
System.out.println("Found");

else
System.out.println("Not Found");


}
}

I want to check if the input is part of the array not the length
something that would look like this when i run different inputs


java Sequence 4
Found
java Sequence -912
Found
java Sequence 555
Not found

When you get the scanner working to retrieve input, you might want to read about for loops and array iteration.

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