Thread: How Compare Integers using the if statement and && operator? Can it be done?

Hello everyone!

I'm working some exercises using an old school book and I got stumped with one of them. With a little help, I was able to solve a previous one dealing with 3 integers...

import java.util.Scanner; // program uses class scanner
 
public class ThreeIntegerSumAvgProductSmallLarge
{
	public static void main ( String args [] )
	{
		Scanner consoleScanner = new Scanner ( System.in );
 
		int number1,
			number2,
			number3,
 
			sum,
			average,
			product,
 
			smallest = 0,
			largest = 0;
 
		System.out.print ( "Please enter 1st integer: " );
			number1 = consoleScanner.nextInt ();
 
		System.out.print ( "\nPlease enter 2nd integer: \n" );
			number2 = consoleScanner.nextInt ();
 
		System.out.print ( "Please enter 3rd integer: \n" );
			number3 = consoleScanner.nextInt ();
 
		sum = number1 + number2 + number3;
		average = ( ( number1 + number2 + number3 ) / 3 );
		product =  number1 * number2 * number3;
 
		if ( number1 > number2 && number2 > number3 )
			largest = number1;
		if ( number2 > number1 && number1 > number3 )
			largest = number2;
		if ( number3 > number2 && number2 > number1 )
			largest = number3;
 
		if ( number1 < number2 && number2 < number3 )
			smallest = number1;
		if ( number2 < number1 && number1 < number3 )
			smallest = number2;
		if ( number3 < number2 && number2 < number1 )
			smallest = number3;
 
		System.out.printf ( "%s%d\n", "The sum of your three numbers is: ", sum );
		System.out.printf ( "%s%d\n", "The product of your three numbers is: ", product );
		System.out.printf ( "%s%d\n", "Your three numbers produced an average of: ", average );
 
		System.out.printf ( "\n%s%d\n", "The largest number out of the three is: ", largest );
		System.out.printf ( "%s%d\n", "The smallest number out of the three is: ", smallest );
	} // end method main
} // end class ThreeIntegerSumAvgProductSmallLarge

...but then, I came across an example that involved 5 integers... and using the same technique in the code above, I was not able to find a solution using the if statements and the && operators. Fortunately, I was able to find the answer, but using a different method (below)...does anyone know how to achieve the same thing just using the 'if', '>', '>' and &&?

 import java.util.Scanner; // Program uses the Scanner class
 
 public class Exercise2_24 // A workbook exercise
 {
 	public static void main ( String args [] ) // main method that begins execution of Java program
 	{
 		//New scanner called 'numberScanner' is created from Scanner class, and takes input from System
 		Scanner numberScanner = new Scanner ( System.in );
 
 
 		// the five variables need to store inputs from user.
 		int int1,
 		    int2,
 		    int3,
 		    int4,
 		    int5,
 
 		    // the variables to store the largest and smallest integers
 		    big,
 		    small;
 
 		System.out.print ( "Please enter the first integer: " ); // integer prompt
 			int1 = numberScanner.nextInt (); // scanner reads input from user and assigns it to int1
 
 		//assigning int1 to the smallest and largest variables...
 		big = int1;
 		small = int1;
 		// ...technicallly at this point, int1 is the smallest and biggest number!
 
 		System.out.print ( "\nPlease enter the second integer: " );
 			int2 = numberScanner.nextInt ();
 
		// if int2 is smaller than the current biggest number then...
		if ( int2 > big )
			big = int2;
		//...then int2 will be the largest # of them all!
 
		// however...
 
		// if the int2 is smaller than the current smallest number then...
		if ( int2 < small )
			small = int1;
		//...then int2 will be the littlest # of them all! (and the cycle repeats...)
 
		System.out.print ( "\nPlease enter the third integer: " );
			int3 = numberScanner.nextInt ();
			if ( int3 > big ) big = int3;
			if ( int3 < small ) small = int3;
 
 		System.out.print ( "\nPlease enter the fourth integer: " );
 			int4 = numberScanner.nextInt ();
 			if ( int4 > big ) big = int4;
			if ( int4 < small ) small = int4;
 
		System.out.print ( "\nPlease enter the fifth integer: " );
 			int5 = numberScanner.nextInt ();
			if ( int5 > big ) big = int5;
			if ( int5 < small ) small = int5;
 
		// Prints out numbers entered by user
		System.out.printf ( "\nThe integers inputted by the user are: %d%s%d%s%d%s%d%s%d",
			int1, ", ", int2, ", ", int3, ", ", int4, ", & ", int5 );
 
 		System.out.printf ( "\nThe largest number entered is: %d", big ); // prints the biggest
 		System.out.printf ( "\nThe smallest number entered is: %d", small ); // prints the smallest
 	}
 }

does anyone know how to achieve the same thing just using the 'if', '>', '>' and &&?

What's wrong with what you came up with in the other thread? It looks OK to me.

if ( int1 > int2 && int1 > int3 && int1 > int4 && int1 > int5 ) big = int1;

-----

I agree with snowguy13, though, what you have now is better: clearer and more suitable for extension to any number of inputs.

If you want something more elegant, try an array.

I agree with marylandfour. If you put all the numbers in to an array, you could avoid conditionals all together and just use Arrays.sort() method.

I think (or at any rate, am assuming) that the idea behind the code was to get used to conditionals and flow of control constructs. Rather than avoiding them with a library method.

But for elegance, yes, Arrays.sort(). Or, if you favour a less retro look, try the collections framework and a List of some sort.