Thread: I am a beginner please help :)

what wrong whit this statment:

while(!code.equals(code1||code2||code3))
{
System.out.print("Ivalid code. Please enter code again: ");
code = in.nextLine();
}

Error msg: bad operand types for binary operator

thanks

My problem is that i wish that the while loops keeps looping until the 'code' inputted is equal to one of the pre-defined code: code1, code2, code3.

System.out.print("CODE: ");
code = in.nextLine();
int quantity=0;

while(!code.equals(code1||code2||code3))
{
System.out.print("Ivalid code. Please enter code again: ");
code = in.nextLine();
}

So i guess !code.equals(code1||code2||code3 is not excepted by the program

Sry for not being very clear to explain my problem. Hope i improve with time hehe.

Ok thanks for your help. I knew that it works in this way but i thought that maybe another method might exist to save the user some lines. What if you have to compare with 50 other integers? Do you have to write the '!code.equals(coseX)' 50 times?

Thanks again!

Yeah, you would, however it seems that you should be checking an array, not a ton of variables. If you put code1, code2, code3....code50 all in a list, you could just do this:

/*
 * PRECONDITION: list is not null and is of the same type of i,
 * which is also not null.
 */
Collections.sort(list);
int ind = Collections.binarySearch(list, i);
if(ind >= 0)
{
  System.out.println(i+" is in "+list+" at index "+ind);
}else
{
  System.out.println(i+" is not in "+list);
}

If it is for an array, u could also use a "for" or a do{...}while()

Or you could do what I just said, which would have less code and most likely be more efficient.