Thread: Need Help on Looping Program!! Beginner!!

I'm having trouble on a program where I am supposed prompt the user for a positive integer and then displays those integers.

My teacher told me to use this:
Initialize a counter to 2
while the counter is less than or equal to the number
if the counter divides the number evenly
display the counter
divide the number by the counter to get a new number
else increment counter by 1

This is what I tried:

import java.util.Scanner;
public class PrimeFactors {
 
    public static void main(String []args) {
 
		Scanner input = new Scanner(System.in);
 
    	int n;
    	int i;
 
    	System.out.println("What is your number?");
    	n = input.nextInt();
 
		for(i = 2;i<=n;i++)
    	while (i <= n)
    	{
		if(i%n == 0)
			System.out.println(i);
		else
			i++;
    	}
 
 
    }
 
 
}

It has an infinite loop. Help?????

To see what the code is doing, add some printlns that print out the values of i and n as it executes.

Once the

if(i%n == 0)

where i%n does equal zero, it won't ever add 1 to i again. Also, when is the program exactly finished?

while (i <= n)
 
    	{
		if(i%n == 0)
			System.out.println(i);
		else
			i++;
    	}

Look carefully. When your program is going to else part? What is the value of i? Why doesn't it change itself?

import java.util.Scanner;
public class PrimeFactors {

public static void main(String []args) {

Scanner input = new Scanner(System.in);


int n;

System.out.println("What is your number?");
n = input.nextInt();

for(int i = 2;i<=n;i++)
while (i <= n)
{
if(i%n == 0){
System.out.println(i);
n=n/i;
}
else
i++;

}


}


}

Okay, I did this. However it just displays the number entered.

And wrap your code in code tags for better readability.