Thread: Evaluating two ints at the same time

Hello Sean448!

Originally Posted by Sean448

What I'm doing is running two different random objects to get two random ints, and then doing an if-else statement to run a different section of code depending on which two random ints are selected. If I set it so that it selects just one random int and then runs an if-else statement based on which single int is selected, it works fine. But I can't get it to evaluate two ints at once. When I try to do this, the code in the if-else statements doesn't run at all.

This continues for all of the remaining possible combinations of the two random ints. Like I said, if I change the code so that only one random int is evaluated, then it will work fine, but when I run it as above, the code inside the if-else statements doesn't run at all. So what am I doing wrong here?

If I were you, i would make the random objects return two values(ie 1 and 2), change the if statements to evaluate these four combinations (1-1, 1-2, 2-1, 2-2). If that worked, I would then expand it. This way you will be able to find the bug easier.

Originally Posted by Sean448

Also, as a side question - is there any way to get it so that the random int objects won't select 0?

The nextInt(int n) method returns an int between 0 (inclusive) and n (exclusive).
Therefore you cannot make it not select 0. But you can add 1 to the value it returns. For example, if you want a random int between 1 and 6 you can have the following statement:
int x = 1 + random.nextInt(6);

Hope it helps.