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Thread: Alphabetical order

  1. #1
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    Default Alphabetical order

    This is a program where the user types a bunch of words and then the program rearranges them into alphabetical order and then prints them.
    But this code keeps crashing on line 35 at "for (int count = 0; count < word1.length() ; count++)". Could anyone tell me whats wrong? (You can only input words that has the same length)

    The error it gives is : java.lang.StringIndexOutOfBoundsException
    it only gives the error when the user doesnt type it in alphabetical order. IDK why

    Here is the code:


    import java.awt.*;
    import hsa.Console;
     
    public class Alphabeticall_order
    {
        static Console c;           // The output console
        public static void main (String[] args)
        {
            c = new Console ();
            c.println ("How many words do you want to put in?");
            int slots = c.readInt ();
            String[] words = new String [slots];
            for (int y = 0 ; y < slots ; y++)
           {
                c.println ("Input the words with the same length");
                words [y] = c.readLine ();
           }
            for (int h = 0 ; h < slots ; h++)
            {
     
                for (int g = 0 ; g < slots - 1 ; g++)
                {
                    words [g] = swaplow (words [g], words [g + 1]);
                    words [g + 1] = swaphigh (words [g], words [g + 1]);
                }
     
            }
            for (int d = 0 ; d < slots ; d++)
                c.println (words [d]);
        }
     
     
        public static String swaplow (String word1, String word2)
        {
            String index = "";
            for (int count = 0; count < word1.length() ; count++)
            {
                if (word1.charAt(count) < word2.charAt(count))
                {
                    index = word1;
                    break;
                }
                else if (word1.charAt (count) > word2.charAt (count))
                {
                    index = word2;
                    break;
                }
            }
            return index;
        }
     
     
        public static String swaphigh (String word1, String word2)
        {
            String index = "";
            for (int count = 0; count < word1.length() ; count++)
            {
                if (word1.charAt (count) > word2.charAt (count))
                {
                    index = word1;
                    break;
                }
                else if (word1.charAt (count) < word2.charAt (count))
                {
                    index = word2;
                    break;
                }
            }
            return index;
        }
    }
    Last edited by sbjibo; May 15th, 2012 at 09:07 PM.


  2. #2
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    Default Re: Alphabetical order

    What exception or error is being thrown?
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    Default Re: Alphabetical order

    Not sure, but your code is assuming that word2 has at least as many characters as word1.

    If it encounters say

    word1 = "mongoose" word2="snake" then you've got a problem.

  4. #4
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    Default Re: Alphabetical order

    Ya i know. It tells the users to enter the words with the same length

  5. #5
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    Default Re: Alphabetical order

    May I ask what the h variable is for. It's not doing anything. Or at least you never use it.

    Also, in the h loop you're going from 0 to slots and in the other one, the inner one, you're going from 0 to slots - 1.

    Unfortunately, I can't manage to import the Console class into JGrasp so it won't even compile for me.

    Also, what happens if some of the characters happen to be the same

    word1 = ostriches
    word2 = penguins

    Your code might leave index as null.
    Last edited by javapenguin; May 15th, 2012 at 09:59 PM.

  6. #6
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    Default Re: Alphabetical order

    It is like a bubble sort. you switch the position of 2 consecutive items in the array. And you loop it for the number of elements the array has. The 'h' variable is to keep track of how many more times you have to loop it

  7. #7
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    Default Re: Alphabetical order

    And to compile, you can use the Scanner method intead of console. But you have to modify the code a bit

  8. #8
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    Default Re: Alphabetical order

    for (; count < word1.length() ; count++)
    {
    if (word1.charAt (count) > word2.charAt (count))
    {
    index = word1;
    break;
    }
    else if (word1.charAt (count) < word2.charAt (count))
    {
    index = word2;
    break;
    }
    }

    SO count is keep going to increase until it reaches value that is different. I am assuming the words are all different but the same length

  9. #9
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    Default Re: Alphabetical order

    Funny, when I used Scanner, it compiled. No exceptions.

    However, it is printing blanks for all the values in array. I think that might be due to index being null when characters happen to be the same.

       import java.awt.*;
       ;
     
       public class Alphabeticall_order
       {
          static java.util.Scanner console;           // The output console
          public static void main (String[] args)
          {
             console = new java.util.Scanner(System.in);
             System.out.println ("How many words do you want to put in?");
             int slots = console.nextInt ();
             String[] words = new String [slots];
             for (int y = 0 ; y < slots ; y++)
             {
                System.out.println ("Input the words with the same length");
                words [y] = console.nextLine ();
             }
             for (int h = 0 ; h < slots ; h++)
             {
     
                for (int g = 0 ; g < slots - 1 ; g++)
                {
                   words [g] = swaplow (words [g], words [g + 1]);
                   words [g + 1] = swaphigh (words [g], words [g + 1]);
                }
     
             }
             for (int d = 0 ; d < slots ; d++)
                System.out.println (words [d]);
          }
     
     
          public static String swaplow (String word1, String word2)
          {
             String index = "";
             for (int count = 0; count < word1.length() ; count++)
             {
                if (word1.charAt(count) < word2.charAt(count))
                {
                   index = word1;
                   break;
                }
                else if (word1.charAt (count) > word2.charAt (count))
                {
                   index = word2;
                   break;
                }
             }
             return index;
          }
     
     
          public static String swaphigh (String word1, String word2)
          {
             String index = "";
             for (int count = 0; count < word1.length() ; count++)
             {
                if (word1.charAt (count) > word2.charAt (count))
                {
                   index = word1;
                   break;
                }
                else if (word1.charAt (count) < word2.charAt (count))
                {
                   index = word2;
                   break;
                }
             }
             return index;
          }
       }

     

    How many words do you want to put in?
    9
    Input the words with the same length
    Input the words with the same length
    mongoose
    Input the words with the same length
    penguins
    Input the words with the same length
    ostriches
    Input the words with the same length
    octopuses
    Input the words with the same length
    tarantula
    Input the words with the same length
    political
    Input the words with the same length
    warmonger
    Input the words with the same length
    Australia













    Last edited by javapenguin; May 15th, 2012 at 10:11 PM.

  10. #10
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    Default Re: Alphabetical order

    it still gives exceptions
    Last edited by sbjibo; May 16th, 2012 at 01:51 PM.

  11. #11
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    Default Re: Alphabetical order

    You could simply store each word in a SortedSet and they would be arranged in alphabetical order then

  12. The Following User Says Thank You to Parranoia For This Useful Post:

    sbjibo (May 16th, 2012)

  13. #12
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    Default

    Quote Originally Posted by Parranoia View Post
    You could simply store each word in a SortedSet and they would be arranged in alphabetical order then
    That's exactly what I was thinking...though I was thinking about a ListSet.

  14. #13
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    Default Re: Alphabetical order

    i figured it out: When you type this
    words [g] = swaplow (words [g], words [g + 1]);
                   words [g + 1] = swaphigh (words [g], words [g + 1]);
    you have type this in its place:
    String p = words [g];
                    String q = words [g + 1];
                    words [g] = swaplow (words [g], words [g + 1]);
                    words [g + 1] = swaphigh (p, q);

    It was not working because words[g + 1] would be equal to words[g] without a variable p to hold words[g] in the unswapped form
    Last edited by sbjibo; May 16th, 2012 at 03:34 PM.

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