Thread: I Seriously Need your Serious Help.

Newbie Question Coming thru. And to sir JPS I am greatfully thank you and sorry. I've fixed it now.
TO the point. This Code now gives me nullpointerExceptions. I tried putting String to it so It won't return as null but it still won't budge.

import java.util.Scanner;
public class RegistrationofEmployees {
 public static final	String emp[][] = new String[4][4];
    public static void main(String[] args) {
 
       	Scanner input = new Scanner(System.in);
 
    	System.out.println("Registration of Employee");
 
    	startPage();
    	System.out.println("\nProgram Terminated...");
 
    }
 
 
 	public static void startPage(){
 
	String employee ="";
 
			Scanner input = new Scanner(System.in);
			System.out.println("Registration of Employee");
			System.out.println("============================================");
			System.out.println("Enter your Choice: ");
			System.out.println("============================================");
			System.out.println("\t\t[a] Register Employee");
			System.out.println("\t\t[b] Time Keeping");
			System.out.println(" ");
			System.out.print("Choose Letter: ");
			String choice1 = input.next();
			if(choice1.length() == 1){
				char choice2 = choice1.charAt(0);
			if (choice2 == 'a' || choice2 == 'A'){
				System.out.println("Lalalalala");
 
			}else if(choice2 == 'b' || choice2 == 'B'){
				searchEmployee(employee);
 
 
 
			}else{
				System.out.println("============================================");
				System.out.println("Invalid Letter");
				System.out.println("============================================");
			}
			}else{
				System.out.println("Invalid String..!");
			}
 
	public static String[] searchEmployee(String empNumber){
		Scanner input= new Scanner(System.in);
		System.out.println("Enter Employee Number: ");
		String empNumber1 = input.next();
		String[] employee = new String[4];
		if(empNumber1.length() < 5 || empNumber1.length() > 5){
			System.out.println("Criteria is invalid.");
			return null;
 
		}else{
			for(int x=0;x<emp.length;x++){
				if(!emp[x][0].equals("")){
					if(emp[x][0].equals(empNumber1)){
						employee[0] = emp[x][0];
						employee[1] = emp[x][1];
						employee[2] = emp[x][2];
						employee[3] = emp[x][3];
						return employee;
						}
					}
			}
		}	System.out.println("Employee number provided not found!");
			return null;
 
 
 
 
 
	}
	public static void data(String emp[][]){
 
		emp[0][0] = "10000";
		emp[0][1] = "John Loudwig";
		emp[0][2] = "Alonsagay";
		emp[0][3] = "Regular Employee";
 
		emp[1][0] = "10001";
		emp[1][1] = "Gienna";
		emp[1][2] = "Belonio";
		emp[1][3] = "Manager";
 
		emp[2][0] = "10002";
		emp[2][1] = "James";
		emp[2][2] = "Arcilla";
		emp[2][3] = "Supervisor";
}

The code is giving me three NullPointerExceptions at these lines :startPage();

  public static void main(String[] args) {
 
       	Scanner input = new Scanner(System.in);
 
    	System.out.println("Registration of Employee");
 
    	startPage();
    	System.out.println("\nProgram Terminated...");
 
    }

At the searchemployee(employee);

if(choice1.length() == 1){
				char choice2 = choice1.charAt(0);
			if (choice2 == 'a' || choice2 == 'A'){
				System.out.println("Lalalalala");
 
			}else if(choice2 == 'b' || choice2 == 'B'){
				searchEmployee(employee);

annnd at this loop under the searchEmployee method

	if(!emp[x][0].equals("")){

It gives me a nullPointerException at those three lines. I tried making a boolean argument on the startpage(); so that when it returns a null, the system will do something.. but it didnt work. I tried try and catch but I have really no idea what to do with it.

Please help me.