Thread: Cannot read last byte of a file...."

Read the API doc for the class's readChar() method and see if you are using it correctly.
What does it say it will do?

Hi,
If you print rcfile.length(), It'll show 27, but this is 26 charachters in your abcd.txt file.
so if you put raf.seek(rcfile.length()-2); the problem will be solved.

may be there is an End of File charachter in text file that you can not see.

Note: It is better the class name starts with capital letter, e.g. Last_byte insted of last_byte

Are you insisting on using RandomAccessFile?
Why don't you use something else like this?

In this code, 10 is the last character in file.

import java.io.*;
 
public class last_byte
{
    public static void main(String args[]) throws FileNotFoundException, IOException
    {
            File rcfile=new File("abcd.txt");
            InputStream in = new FileInputStream(rcfile);
            Reader reader = new InputStreamReader(in);
 
            int intCh;
            int theLastChar = 10;
 
            while ((intCh = reader.read()) != -1) {
                char ch = (char) intCh;
                if (intCh != 10) {
                	theLastChar = ch;
                }
            }
            System.out.println((char)theLastChar);
    }
 
}

Thanxx.....@Banafshe..'
It worked...'

If you look at the contents of the file in a hex editor you will see what it contains.
Most files created with a text editor write out files with one character per byte.
If you save text in Unicode format (wordpad will do it) it will use two bytes per character.