Thread: HELP ME TO SOLVE THIS JAVA FOR LOOP PROGRAM

WRITE JAVA FOR WHILE SYNATX CODE GIVE OUT

1^1 + 2^2 + 3^3 + 4^4 + 5^5

Result=3413

I am not sure what your code is but one way of writing this could be:

int i = 0;
while(true)
{
take the power of i to itselft (ie. i^i)
then add it to some instance variable.
 
after that increment i.
keep doing this forever and ever,
unless you need to have a limit for how long it needs to go.
in which case the while loop parameter could be "while(i < 40)" for example.
}

 
long val = /*start value for val*/ ;
 
for(int i = 1; i <= /*upper limit*/; /*increment*/)
{
val += //mathematical expression for the series
}

//this program give output 1^3 + 2 ^3 + 3^3 + 4^4....upto n input numbers.......

//but now i wana to get out put in this form 1^1 + 2^2 + 3^3 + 4^4 .....upto n input numbers......
//pls help me to make this program..........




import java.util.*;

class cubeseries{
public static void main(String arg[]){
int s=0 , num ,i;
Scanner input = new Scanner(System.in);
System.out.print("ENTER NUMBER : ");
num = input.nextInt();

for(i = 1 ; i <= num ; i++)

s = s+i*i*i;
System.out.print(s);


}
}