Thread: data values help

hello i am new to java. I don't get why tempNumber only catches 2 digit numbers. and when I choose "2" it doesnt respond first time. When it displays the menu again and I enter again "2" then it works.

	import java.io.*;
	//import java.math.*;
	public class java_prime{
		//We will create two class arrays, these
		//Can be used by all the methods in the class
		static int number[] = new int[100];
		static String name[] = new String[100];
		//We will create a counter, this will help us
		//remember how many names and numbers we are storing
		static int counter = 0;
		//Main method
		public static void main(String[] args) throws IOException{
			String tempName = null;
			int tempNumber = 0;
			//Create a Buffered reader for input, you do remember how don't you?
			BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
			//Here we output our Menu
			displayMenu();
			//Here we get user input
			String temp = in.readLine();
			//Loop until the use wants to quit
			while(temp!="3"){
				if(temp.equals("1")){
					System.out.print("Enter a new Name: ");
					tempName = in.readLine();
					System.out.println();
					System.out.print("Enter a new Number: ");
					tempNumber = in.read(); 
					//Here we call the method to add the record
					addEntry(tempName, tempNumber);
				}else if(temp.equals("2")){
					//In here we call the method to output the records
					showRecords();
				}
				//Display the menu again and ask for input again
				displayMenu();
				temp = in.readLine();
			}
		}
		//Here is all the methods you will need!
		public static void  addEntry(String tempName, int tempNumber){
			name[counter] = tempName;
			number[counter] = tempNumber;
			counter++;
		}
		public static void displayMenu(){
			System.out.println("\n\n\n");
			System.out.println("WELCOME TO THE JAVA PDA - DESKTOP VERSION\n\nWhat would you like to do today?\n\n1. Enter a new Name and Number\n2. View all names and Numbers\n3. Quit");
		}
		public static void showRecords(){
			int i;
			System.out.println("Name\t\t\t\tNumber");
			for(i = 0; i!=counter;i++){
				System.out.println(name[i]+"\t\t\t\t"+number[i]);
			}
		}
	}

Try debugging the code by printing out the value of tempNumber right after it is read in so you can see what is being read.


Please copy the full contents of the console for when you execute the program and post it here.

On windows: To copy the contents of the command prompt window:
Click on Icon in upper left corner
Select Edit
Select 'Select All' - The selection will show
Click in upper left again
Select Edit and click 'Copy'

Paste here.

When you execute the code, it writes to the console and you enter data on the console.
Can you copy the contents of the console and paste it here so we can see what is printed by the program and what you entered as data to the program? Also add some comments that describe what the problem was with the way the program executed.

One problem I see is the use of != to compare Strings. You need to use the equals() method to compare the contents of Strings.

49 is what the read() method returns when it reads '1'. Read the API doc for the method for details.
To see '1' vs 49, print this: (char)49

why would/does it reads '1' when I enter 123455.

Read the API doc for the read() method. It says that it reads a single character.

To get an int value you need either to
read a String and convert it to int using the Integer class's method
or use the Scanner class to read user input. The Scanner class has methods to read and convert character input to an int value.