Thread: Funny Behaviour

Here is a little program I wrote to help me memorize my student ID #. I will * out the actual number but here is my code.

import java.util.Scanner;
class baylorID {
	public static void main(String[] args){
		//clear the console
		System.out.print("\033[H\033[2J");
		System.out.flush();
 
		//store correct baylor id in a string
		String correctID = "*********";
		String inputID = new String();
		String quit = "quit";
		int numCorrect = 0;
		int numIncorrect = 0;
		int netCorrect = 0;
 
		//ask user for student id
		while (netCorrect < 10) {
			System.out.print("\033[H\033[2J");
			System.out.flush();
			Scanner scan = new Scanner(System.in);
			System.out.println("What is your Student ID? \t Type 'quit' to exit.");		
			inputID = scan.next();
 
		//compare the two
			if (inputID.equals(quit)) {
				numCorrect = 12;
				numIncorrect = 1;
			}
			if (inputID.equals(correctID)) {
				System.out.println("Correct! You remembered it!");
				numCorrect += 1;
				System.out.println(numCorrect);
			} else {
				System.out.println("Incorrect. Try Again.");
				numIncorrect += 1;
				System.out.println(numIncorrect);
			}
			netCorrect = numCorrect - numIncorrect;
		}
	}
}

It compiles and runs successfully. However, when I type quit, it does not do what I want.

What I Want:
The program to stop running

What Happens:

What is your Student ID? 	 Type 'quit' to exit.
quit
Incorrect. Try Again.
2

Then it stops running

I'm not sure why you need to "clear the console". I believe you may be confusing the scanner with the buffered writer class.

As far as i know you just need to close it after use with scan.close()

Try and declare the scanner at the top, so it has scope beyond the while loop.

What does System.out.print("\033[H\033[2J"); do?

One you have looked at the above, I think you need to review this part of the code:

//compare the two
			if (inputID.equals(quit)) {
...
}