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Thread: Please Help. Urgent. For loops and printing to output statement.

  1. #1
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    Default Please Help. Urgent. For loops and printing to output statement.

    Hello all,


    I am making a program that takes user entered amounts and makes a table of random numbers..

    However,

    I am trying to make the user entered amounts show up in the terminal window and output file...I cannot figure this out after hours of trying.

    Someone PLEASE help!

    I will really appreciate..

    here is my current code

    It is printing fine in the terminal window but not the output file..I need the same thing in the terminal and output ||


     rnumber = randomGenerator.nextInt(hnumber);
     
               System.out.println();
               int counter = rnumber;
               for (int rows = 1; rows <= rownumber; ++rows) 
                    {
                    for (int columns = 1; columns <= cnumber; ++columns) 
                    {
     
                        rnumber = randomGenerator.nextInt(hnumber);
                        rnumber++;
                        System.out.printf("%4d", rnumber);
     
                        PrintWriter myOut;
                        try { myOut = new PrintWriter (new FileOutputStream("out6.dat"));
     
     
     
     
                                    myOut.printf("%4d", rnumber);
     
     
     
                        }
                        System.out.println();
                    }
                    myOut.close();
                }
     
                        catch (IOException e) {
                            System.out.println("exception is "+e.getMessage());
                        }
    Last edited by pbrockway2; March 16th, 2013 at 11:09 PM. Reason: code tags added


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Please Help. Urgent. For loops and printing to output statement.

    What is written to the output file?
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: Please Help. Urgent. For loops and printing to output statement.

    Quote Originally Posted by Norm View Post
    What is written to the output file?

    UPDATE:

    This is what I've gotten so far.. I will post my whole code & terminal window &output file.. The problem is my program is not giving me the correct output file but the terminal window is correct..


    What is in the terminal window:
    "
    This program will generate random numbers.

    Enter the lowest value possible (0 or 1): 1

    Enter the highet value possible: 100

    How many numbers would you like?: 25

    How many rows of numbers would you like?: 5

    How many columns of numbers would you like?: 5

    90 50 59 55 65
    34 75 35 72 42
    98 67 8 39 42
    31 61 98 41 60
    81 69 74 75 1


    "

    All of the above is user entered information.

    Output file has just one number in it. The number 1. However it chnages everytime with a different number, but only one number.

    I need the output file to be the same consistenly with the terminal window. Someone please help. I've spent many many hours on this so far and I need to finish it.










    import java.util.Scanner;
    import java.util.Random;
    import java.io.*;

    public class project6
    {
    public static void main (String [] args)
    {

    Scanner keyboard = new Scanner(System.in);
    Random randomGenerator = new Random();
    int number, hnumber, tnumber, rnumber, rownumber, cnumber;

    System.out.println("This program will generate random numbers.");
    System.out.println();



    do {
    System.out.print("Enter the lowest value possible (0 or 1): ");
    number = keyboard.nextInt();
    String junk = keyboard.nextLine();
    if ((number == 0) || (number == 1)){
    break;

    }
    else{
    System.out.println("Sorry, you need to enter a zero or 1 for the lowest number. \nTry again.");


    }
    } while ((number ==0)||(number ==1));

    System.out.print("\nEnter the highet value possible: ");
    hnumber = keyboard.nextInt();
    String junk = keyboard.nextLine();

    System.out.print("\nHow many numbers would you like?: ");
    tnumber = keyboard.nextInt();
    junk = keyboard.nextLine();

    System.out.print("\nHow many rows of numbers would you like?: ");
    rownumber = keyboard.nextInt();
    junk = keyboard.nextLine();

    System.out.print("\nHow many columns of numbers would you like?: ");
    cnumber = keyboard.nextInt();
    junk = keyboard.nextLine();








    rnumber = randomGenerator.nextInt(hnumber);
    PrintWriter myOut;
    System.out.println();
    int counter = rnumber;

    for (int rows = 1; rows <= rownumber; ++rows)
    {
    for (int columns = 1; columns <= cnumber; ++columns)
    {

    rnumber = randomGenerator.nextInt(hnumber);
    rnumber++;
    System.out.printf("%4d", rnumber);




    try { myOut = new PrintWriter (new FileOutputStream("out6.dat"));

    myOut.printf("%4d", rnumber);

    myOut.close();
    }



    catch (IOException e) {
    System.out.println("exception is "+e.getMessage());
    }



    }
    System.out.println();
    }



    }
    }

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: Please Help. Urgent. For loops and printing to output statement.

    Output file has just one number in it.
    That sounds like the code is writing the current number to the file replacing all the other values written to the file. Only the last number written will be in the file.

    If you want all the data to be written to the file, create the file BEFORE the loop, write to the file INSIDE the loop,
    and close the file AFTER the loop.


    Please edit your post and wrap your code with
    [code=java]
    <YOUR CODE HERE>
    [/code]
    to get highlighting and preserve formatting.
    If you don't understand my answer, don't ignore it, ask a question.

  5. The Following User Says Thank You to Norm For This Useful Post:

    timisaballer23 (April 9th, 2013)

  6. #5
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    Default Re: Please Help. Urgent. For loops and printing to output statement.

    Thanks for the reply. I'm trying to do that however it doesnt really make sense how?

    This is where I'm at.

    <
     { try { myOut = new PrintWriter (new FileOutputStream("out6.dat"));
     
                              myOut.printf("%4d", rnumber);
     
     
                        }
     
               for (int rows = 1; rows <= rownumber; ++rows) 
                    {
                    for (int columns = 1; columns <= cnumber; ++columns) 
                    {
     
                        rnumber = randomGenerator.nextInt(hnumber);
                        rnumber++;
                        System.out.printf("%4d", rnumber);
     
                    }
                    System.out.println();
                }
     
                myOut.close();
                catch (IOException e) {
                            System.out.println("exception is "+e.getMessage());
                        }
                    }
    >
    Last edited by Norm; March 17th, 2013 at 08:19 AM. Reason: removed spaces from code tag

  7. #6
    Super Moderator Norm's Avatar
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    Default Re: Please Help. Urgent. For loops and printing to output statement.

      myOut.printf("%4d", rnumber);
    That code will write one number to a file.

    Where is the code to write the rest of the numbers to the file?
    If you don't understand my answer, don't ignore it, ask a question.

  8. The Following User Says Thank You to Norm For This Useful Post:

    timisaballer23 (April 9th, 2013)

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