Thread: Help for my codes

Hello, im new in java programming can someone help me, to fix this problem im making a program a id searching program , that the user will be ask to input an student id and if the STUDENT ID is found the program will execute the information for that id and if the id is not found the program will display "ID NOT FOUND"

example of Student id and other information for that id
Untitled-1.jpg

id searching(input the Student ID
i for this example i will ender the student id
"lol-1:)
input.JPG

if id is found display the other information in that id
output.JPG

if id is not found this will display
not.JPG

*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package student.information.pkg1;
 
import javax.swing.JOptionPane;
 
/**
 *
 * @author +++++
 */
public class StudentInformation1 {
 
    /**
     * @param args the command line arguments
     */
 
    public static void main(String[] args) {
        // TODO code application logic here
 
        String Input ="";
 
        String Student [][] = {{"lol-0", "meow0", "superman0", "batman0"},
            {"lol-1", "meow1", "superman1", "batman1"},
            {"lol-2", "meow2", "superman2", "batman2"},
            {"lol-3", "meow3", "superman3", "batman3"},
            {"lol-4", "meow4", "superman4", "batman4"},
            {"lol-5", "meow5", "superman5", "batman5"}};
 
 
        boolean Superman = false;
        Input = JOptionPane.showInputDialog(null, "Enter Student ID");
 
 
        for (int x = 0; x < Input.length() ; x++){
            for (int y = 0; y <  Student[x].length; y++){
                Superman = true;
                break;
            }
            if (Superman){
                System.out.println( Input + " found" );   
            }
            else{
            System.out.println(Input +  " not found ");
         }

hope you understand me , BTW you can edit that code


#JOptionPane
#array elements
#string

my problem sir for that program, if i type the student id , the program is not find the id and other information for that elements , or it find but it have a error

String Student [][] = {{"lol-0", "meow0", "superman0", "batman0"},
            {"lol-1", "meow1", "superman1", "batman1"},
            {"lol-2", "meow2", "superman2", "batman2"},
            {"lol-3", "meow3", "superman3", "batman3"},
            {"lol-4", "meow4", "superman4", "batman4"},
            {"lol-5", "meow5", "superman5", "batman5"}}

the id is that "lol-0 to lol-5" and if the id is found the name and other elements for that line will be display

e.g
student id input : ol-1


the student id is found so the program will display the other elements in that id
name :meow1
other 1:superman1
other 2:batman1

yes sir, i having problem with writing the code to find the matching id,

problem : having problem with writing the code to find the matching id and to display the elements on that line
code

import javax.swing.JOptionPane;
 
/**
 *
 * @author +++++
 */
public class StudentInformation1 {
 
    /**
     * @param args the command line arguments
     */
 
    public static void main(String[] args) {
        // TODO code application logic here
 
        String Input ="";
 
        String Student [][] = {{"lol-0", "meow0", "superman0", "batman0"},
            {"lol-1", "meow1", "superman1", "batman1"},
            {"lol-2", "meow2", "superman2", "batman2"},
            {"lol-3", "meow3", "superman3", "batman3"},
            {"lol-4", "meow4", "superman4", "batman4"},
            {"lol-5", "meow5", "superman5", "batman5"}};
 
 
        boolean Superman = false;
        Input = JOptionPane.showInputDialog(null, "Enter Student ID");
 
 
        for (int x = 0; x < Input.length() ; x++){
            for (int y = 0; y <  Student[x].length; y++){
                Superman = true;
                break;
            }
            if (Superman){
                System.out.println( Input + " found" );   
            }
            else{
            System.out.println(Input +  " not found ");
         }

sir the program should ask the user to input the student id and search the student id that the user has been input, and for example if i input the lol-1 as a student id the line for that lol-1 should display the , meow0, superman0, batman0 not just a straight line that will post, but it will display like this

student id : lol-1
name :meow1
other 1:superman1
other 2:batman1

#sorry

Do you need to use a 2-D array? Why not use a normal array for each record (read from a file perhaps)?

Originally Posted by Starstreak

Do you need to use a 2-D array? Why not use a normal array for each record (read from a file perhaps)?

i think i need to use a 2-D array , but i don't know how to code it


(sorry im just a noob)

String  Student [][] = {{"lol-0", "meow0", "superman0", "batman0"},
            {"ID-1", "meow1", "superman1", "batman1"},
            {"ID-2", "meow2", "superman2", "batman2"},
            {"ID-3", "meow3", "superman3", "batman3"},
            {"ID-4", "meow4", "superman4", "batman4"},
            {"ID-5", "meow5", "superman5", "batman5"}};
 
 
        String input = JOptionPane.showInputDialog(null, "Input Here");
        int i;
        int j = 0;
        boolean foundIt = false;
 
    search:
        for (i = 0; i < Student.length; i++) {
            for (j = 0; j < Student[i].length;
                 j++) {
                if ( Student[i][j] == null ? input == null : Student[i][j].equals(input)) {
                    foundIt = true;
                    break search;
                }
            }
        }
 
        if (foundIt) {
            JOptionPane.showMessageDialog(null, "Found the"
                    + "id  \n\n" + input);
 
        } else {
            JOptionPane.showMessageDialog(null, input + " ID NOT FOUND");
 
        }

now , the program is can find the ID in the element, but my problem is how can i display the column that i search using the id?

The use of labels in Java is generally discouraged if we can help it.

If the program tries to find ID-4, we get the Student[3][0] {Student[i][j]} where 3 is the row and 0 is the column containing the ID number, then you just need to display the other elements of that particular row. We only have 0,1,2,3 to choose from and 0 is the ID number.

Originally Posted by Starstreak

The use of labels in Java is generally discouraged if we can help it.

If the program tries to find ID-4, we get the Student[3][0] {Student[i][j]} where 3 is the row and 0 is the column containing the ID number, then you just need to display the other elements of that particular row. We only have 0,1,2,3 to choose from and 0 is the ID number.

ok sir can you code/show sample code sir? to display the element in the choosing row.

advance thank you sir

Look where your code writes "found it". That i value will be the row you need.

The row where you found the correct ID is i. So now you just need to output the j's you want.

Originally Posted by Norm

Look at what is in the array. Each row has data for one student. One of the columns in the row has the student id.
The search loop should look at the student id in each row. That can be done with a single loop.
Pseudo code:
begin loop through rows of array
does this row have desired student id
if yes, this row has desired data for printing
move to next row
end loop

how to write Pseudo code sir in java? and add that into my project?

Originally Posted by Starstreak

Look where your code writes "found it". That i value will be the row you need.

The row where you found the correct ID is i. So now you just need to output the j's you want.

sir like these?

if (foundIt) {
            JOptionPane.showMessageDialog(null, "Found the "
                    + " id  \n\n" + input + "\n" + foundIT );
 
        } else {
            JOptionPane.showMessageDialog(null, input + " ID NOT FOUND");
 
        }

Originally Posted by Norm

Post the search code you are working on.

The pseudo code I posted was a list of the steps the program could take to do the search. The search is done in a simple loop that looks at each row for the desired student id.

public static void main (String []args)
    {
    String  Student [][] = {{"ID-0", "meow0", "superman0", "batman0"},
            {"ID-1", "meow1", "superman1", "batman1"},
            {"ID-2", "meow2", "superman2", "batman2"},
            {"ID-3", "meow3", "superman3", "batman3"},
            {"ID-4", "meow4", "superman4", "batman4"},
            {"ID-5", "meow5", "superman5", "batman5"}};
 
 
        String input = JOptionPane.showInputDialog(null, "Input Here");
        int i;
        int j = 0;
        boolean foundIt = false;
 
    search:
        for (i = 0; i < Student.length; i++) {
            for (j = 0; j < Student[i].length;
                 j++) {
                if ( Student[i][j] == null ? input == null : Student[i][j].equals(input)) {
                    foundIt = true;
                    break search;
                }
            }
        }
 
        if (foundIt) {
            JOptionPane.showMessageDialog(null, "Found the "
                    + " id  \n\n" + input + "\n" );
 
        } else {
            JOptionPane.showMessageDialog(null, input + " ID NOT FOUND");
 
        }

my problem, how can i display the element in the column, using the ID that i search ?

for e.g i search
ID-3 and ID-3 column the other will also display, but in a new line, like these
meow3
superman3
batman3