Thread: Java sequential search.

I'm working on sequential search and this is my code to search a String. The problem I have is that once the array is found, it stop. I was wondering what if there are more than one occurrence of that String in the array. I'm trying to modify my code so it find all the occurence and print it. I thought of removing the "break" but then even if I remove it, the code would replace the "found" index by the next occurence that it find, so my program results in printing the last match that it find instead of all of them. Can anyone help me fix this? Thanks

public static void findPerson(Assignment[] r, String toFind)
	{
	    int found = -1;
 
	    for(int i = 0; i < r.length; i++)
	       if (r[i].getPerson().compareTo(toFind) == 0)
	           {
	               found = i;
	               break;
	           }
        if (found != -1)
        {  // we have found the person
           System.out.println("We found " + toFind + " in the roster: ");
           System.out.println(r[found]);
        }
        else
           System.out.println(toFind + " is not in the roster");
	}

I .add(found) onto the arrayList, is there a way to check if an ArrayList contains elements? Since the "found" only get added when the String match, if there no string match then there be nothing inside the list, so I want to check whether the list contains elements. Thanks

Found it. Thanks!