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Thread: need help in exception handling

  1. #1
    Junior Member
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    Angry need help in exception handling

    I m designing a demo for my real application i m just testing what happen when event occur
    here's my code when i press button the catch block run

    private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {

    String str=jTextField1.getText();
    String oldpass=new String(jPasswordField1.getPassword());
    String newpass1=new String(jPasswordField2.getPassword());
    String newpass2=new String(jPasswordField3.getPassword());
    if(oldpass.equals("") && newpass1.equals("") && newpass2.equals("")){
    JOptionPane.showMessageDialog(null,"Pls Enter the Username and password");
    }
    else
    {

    try
    {
    Class.forName("com.mysql.jdbc.Driver");
    Connection con=DriverManager.getConnection("jdbc:mysql://localhost:3306/ims","root","root");
    String s="select * from admin where Admin_pw=123";
    Statement st=con.createStatement();
    ResultSet rs=st.executeQuery(s);


    while(rs.next())
    {

    String y=rs.getString("Admin_id");


    JOptionPane.showMessageDialog(rootPane, y);
    }}
    catch(Exception e)
    {
    JOptionPane.showMessageDialog(null,ERROR);
    }
    }
    Last edited by gauravdudeja; April 8th, 2013 at 05:55 AM. Reason: format again


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: need help in exception handling

    Please edit your post and wrap your code with code tags:
    [code=java]
    <YOUR CODE HERE>
    [/code]
    to get highlighting and preserve formatting.

    What problem are you having?
    If you don't understand my answer, don't ignore it, ask a question.

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