Thread: Reading data from a file into parallel arrays

hi all,

I am having a problem reading the data from a text file into my array. it skips every other character and string in the text file

heres my code

import java.io.*;
import java.util.Scanner;

public class Morse
{
public static void main(String [] args) throws IOException
{
File file = new File("Morse.txt");
Scanner input = new Scanner(file);
String sentence;



char[] characters = new char[36];
String[] symbols = new String[36];





for(int i = 0; i < characters.length; i++)
{
for(int j = 0; j < symbols.length; j++)
{
char characs = input.nextLine().charAt(0);
String syms = input.nextLine();

characters[i] = characs;
symbols[i] = syms;

System.out.print(characters[i] + " " + symbols[i] + "\n");

}
}
}
}

and its returning this

1 2 ..---
3 4 ....-
5 6 -....
7 8 ---..
9 0 -----
A B -...
C D -..
E F ..-.
G H ....
I J .---
K L .-..
M N -.
O P .--.
Q R .-.
S T -
U V ...-
W X -..-
Y Z --..

It's a program for translating a sentence into morse code. The file morse.txt
Has characters 1-9 . , ? and A-Z
And the morse code translation right next to character
I want to read the contents of the file and fill the array so it'll display like this

1 ...
2 ...
3 ...
4 ...
...
...
...
...
A ...
B ....
C ...
D ...
And etc until all the lines are read

char characs = input.nextLine().charAt(0);  //This read a line
String syms = input.nextLine();  //This reads another line

Given your input format, I would read a line, then split it in two using say the space character as delimiter. Then feed your characters and symbols arrays with the splitted line. There is probably a better way but I am just a beginner.

Yes but isn't that the method you use when using scanner methods for a string?

Originally Posted by Norm

Think about this problem and what the code is doing.
What happens to the data following the "1" on the first line?

im not quite sure. I think its reading the line at 1 in the position of the array. it goes through the loop 36 times because there are 36 lines in the file
it stores the data at position i and loops around until finished?

It is not the number of lines in your file being scanned that drives the number of loops. It's the conditions in the for loops. Well unless you have a break condition in the loops.
If the application you use allows you to set breakpoints and step through the codes, you should do so. You will be surprise by the number of loops being executed.

well i edited my code to look like this with one loop

 
for(int i = 0; i < characters.length; i++) 
      { 
         char characs = input.nextLine().charAt(0);
         String syms = input.nextLine();
 
         characters[i] = characs;
         symbols[i] = syms;
 
         System.out.println(characters[i] + " " + symbols[i]);
 
      }

--- Update ---

i get the same display