Thread: How to print information from an array

When I run the application, the memory address prints to the screen. How do I get it to print the information? This is an example of what it is reading from the file.

Jason White
265325222
31
Computer Science



import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class Test
{
public static void main(String[] args)
{
String lName = null, fName = null, uid = null, major = null;
int hours = 0, i = 0, ctr = 0;

Test[] students = null;
File input = new File("Enrollment.txt");
Scanner in;

students = new Test[30];

try
{
in = new Scanner(input);

while (in.hasNextLine() && i < students.length)
{
fName = in.next();
lName = in.nextLine();
uid = in.nextLine();
hours = in.nextInt();
in.nextLine();
major = in.nextLine();

students[i] = new Test();

System.out.println(students[ctr] = new Test());

i++;
}

ctr++;
}

catch (FileNotFoundException e)
{
System.out.println("File not found.");
}
}
}

It may not be causing a problem right now but have you tried using hasNext() instead of hasNextLine() as the latter may return true even if there is nothing in the next line.

As for your actual question, it prints the memory address because you're trying to handle the array of objects as though it were just a single object. Your problem can be fixed by using System.out.println(Arrays.toString(yourArray)); . If the array contains other arrays, then you would use System.out.println(Arrays.deepToString(yourArray)) ;. In both cases, you must first import java.util.Arrays.

I changed hasNextLine() to hasNext(). System.out.println(Arrays.toString(yourArray)); and System.out.println(Arrays.deepToString(yourArray)) ; didn't seem to work. They both printed the memory address along with a bunch of "null's".

that works, thanks