Thread: What Am I Doing Wrong With A Slot Machine Game?

So I am creating a slot machine game were it plays and then picks a random number between 1-10 and then ask the user if he wants to play again if they put in y they play again and if no it stops. So What Am I doing wrong? Sorry the problem is that I can see would you like to play again but I can actually get it to generate the numbers and then have it print out would you like to play again.

<YOUR CODE HERE>
package HW10;
 
import java.util.Scanner;
 
public class HW10 {
 
 
	public static void main(String[] args) 
	{
 
		//This header explains what the program does
		System.out.println("This program randomly generates a number between 1 and 10");
		//Declares variables
		String another = "y";
		int slot1; 
		int slot2; 
		int slot3;
 
 
		//Ask the use to input a yes or a no.
        Scanner keyboard = new Scanner (System.in);
 
		System.out.print("Would you like to continue y or n:");
		another = keyboard.toString();
 
 
 
		//Add comments
		while(another.equalsIgnoreCase("y"));
 
		{
		slot1 = (int) (Math.random() *(10));
		slot2 = (int) (Math.random() *(10));
		slot3 =(int) (Math.random() *(10));
		}
		slot1 = slot2 = slot3 = slot2;
 
 
	}
 
}

as far as I understand u want it to calculate the numbers again if the user types "y", so u just have to suround it all with a while loop, not just slot1. slot2 and slot3, then it will calculate the random numbers until the user write something else than "y" . And u must use the Scanner reference, keyboard to scan the next word, or line, keyboard.nextline() .
like this:

 
import java.util.Scanner;
 
public class HW10 {
 
 
	public static void main(String[] args) 
	{
 
		//Declares variables
		String another = "y";
		int slot1; 
		int slot2 = 0; 
		int slot3;
 
		while(another.equalsIgnoreCase("y")) {
		//This header explains what the program does
		System.out.println("This program randomly generates a number between 1 and 10");
 
		//Ask the use to input a yes or a no.
                Scanner keyboard = new Scanner (System.in);
 
		System.out.print("Would you like to continue y or n:");
		another = keyboard.nextLine();
 
 
 
		//Add comments
 
		slot1 = (int) (Math.random() *(10));
		slot2 = (int) (Math.random() *(10));
		slot3 =(int) (Math.random() *(10));
 
		slot1 = slot2 = slot3 = slot2;
            }
 
	}
 
}

[QUOTE=Skeim;110441]as far as I understand u want it to calculate the numbers again if the user types "y", so u just have to suround it all with a while loop, not just slot1. slot2 and slot3, then it will calculate the random numbers until the user write something else than "y" . And u must use the Scanner reference, keyboard to scan the next word, or line, keyboard.nextline() .
like this:
[code=java]

import java.util.Scanner;

public class HW10 {


public static void main(String[] args)
{

//Declares variables
String another = "y";
int slot1;
int slot2 = 0;
int slot3;

while(another.equalsIgnoreCase("y")) {
//This header explains what the program does
System.out.println("This program randomly generates a number between 1 and 10");

//Ask the use to input a yes or a no.
Scanner keyboard = new Scanner (System.in);

System.out.print("Would you like to continue y or n:");
another = keyboard.nextLine();



//Add comments

slot1 = (int) (Math.random() *(10));
slot2 = (int) (Math.random() *(10));
slot3 =(int) (Math.random() *(10));

slot1 = slot2 = slot3 = slot2;
}

}

}
Awesome thanks! I I also had to print out the number it generated but that was easy and its working now!