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Thread: How to find where the biggest number is in an array

  1. #1
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    Default How to find where the biggest number is in an array

    Hi i've been trying to figure out where to find the biggest number in an array. I know how to find the biggest number but i need to find out where the biggest number is, like which row or whatever it's in.

    import java.util.Scanner;
    public class array {
     
    	public static void main (String args[]) {
     
    	Scanner keyboard = new Scanner(System.in);
     
    	int r[] = new int[50];
    	int n=0;
    	int x, bigSoFar;
     
    	System.out.print("Enter list: ");
    	x = keyboard.nextInt();
     
    	while( x!= -999); {
    		r[n] = x;
    		n++;
    		x = keyboard.nextInt();
    	}
     
    	for(int k = 0; k < n; k++)
    		if(r[k]> bigSoFar) {
     
    			bigSoFar = r[k]; 
    		}	
     
    		System.out.println(r[k]); 
     
    	}	
    }

    Although first i'm having trouble trying to get my first code to work, i keep getting this error
    array.java:34: error: cannot find symbol
    System.out.println(r[k]);
    ^
    symbol: variable k
    location: class array
    1 error


  2. #2
    Super Moderator jps's Avatar
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    Default Re: How to find where the biggest number is in an array

    Check the { }
    It seems the compiler believes k is not defined within scope every time it is being used.
    Look at line 34's use of k

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    Default Re: How to find where the biggest number is in an array

    k is defined as k=0 inside the parenthesis and as for the braces, where else could i place them?

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    Default Re: How to find where the biggest number is in an array

    Check the positioning of the { } again. For some reason the scope of the for loop does not include k on line 34.
    class ForDemo {
        public static void main(String[] args){
             for(int i=1; i<11; i++){
                  System.out.println("Count is: " + i);
             }
             for(int i=1; i<11; i++)
             System.out.println("Count is: " + i);
             System.out.println("I am outside the loop);
        }
    }
    If the for loop is not followed by a curly brace, but instead followed by a statement ending with a semicolon, the scope of the for loop terminates at the semicolon. Demonstrated by the class above, a modified version from the java for loop tutorial

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    Default Re: How to find where the biggest number is in an array

    ok I fixed it and I was able to compile it but now whenever i try to put a list in in the command prompt it will just sit there and not do anything, just freeze and think. I can't figure it out

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    Default Re: How to find where the biggest number is in an array

    Post updated code.
    Improving the world one idiot at a time!

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    Default Re: How to find where the biggest number is in an array

    import java.util.Scanner;
     
    public class array {
     
    	public static void main (String args[]) {
     
    	Scanner keyboard = new Scanner(System.in);
     
    	int r[] = new int[50];
    	int n=0;
    	int x, bigSoFar=0;
     
    	System.out.print("Enter list: ");
    	x = keyboard.nextInt();
     
    	while( x!= -999); {
     
    		r[n] = x;
    		n++;
    		x = keyboard.nextInt();
     
    	}
     
    	for(int k = 0; k < n; k++){
    		if(r[k] > bigSoFar) {
     
    			bigSoFar = r[k]; 
    		}	
     
    		System.out.println(r[k]); 
    		}
     
    	}
     
     
    }

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    Default Re: How to find where the biggest number is in an array

    it will just sit there and not do anything, just freeze and think.
    Is it waiting for the user to enter more data? What happens when more data is typed in?
    What does it do if -999 is entered?

    Add some calls to the println statement to print out messages as the code executes to show you where it is executing.
    If you don't understand my answer, don't ignore it, ask a question.

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