Thread: return type

public class Name {
static int a;
int b=0;
public void fuck(int d){
a=a+1;
b=b+1;
System.out.println(a);
System.out.println(b);
System.out.println(d);
return ;

the function is void type.. and in the end i also wrote return..but no value...
the function runs with no error... why return is not creating a problem

because you exit that "fuck" methode and it continues in the main methode. Return exits out of a methode and break breaks out of loops and if statments

void int function_name()
{
///code
return variable_int;
}

You cant use "void int function_name(){}" because you have two return types and every methode only can have one.

Here some examples(these are from a entitybase class but the prisiple is the same)

private double x, y;
	private double height, width;
	private double velX, velY;
	private boolean alive;
 
	//accessor
	public boolean getAlive(){return alive;}
	public double getX(){ return x;}
	public double getY(){ return y;}
	public double getHeight(){return height;}
	public double getWidth(){return width;}
	public double getVelX(){return velX;}
	public double getVelY(){return velY;}
 
	//mutators
	public void setAlive(boolean alive){this.alive = alive;}
	public void setX(double x){this.x = x;}
	public void setY(double y){this.y = y;}
	public void incX(double i){this.x += i;}
	public void incY(double d){this.y += d;}
	public void setHeight(double height){this.height = height;}
	public void setWidth(double width){this.width = width;}
	public void incHeight(double i){this.height += i;}
	public void incWidth(double i){this.width += i;}
	public void setVelX(double velX){this.velX = velX;}
	public void setVelY(double velY){this.velY = velY;}

The accesor methodes will when used return a value(possible to be calculated within this methode it self). While the mutator methodes can change valeu and never have to return something because of their void return type. There is always 1 return type in every methode(void,int,double,float,string etc).

And use the code tags for nice code layout.

you can have a return in a void method you just cant have it return anything

return; works

return anythingHere; shouldnt