Thread: String to Double Conversion

I'm sure this is something very simple, but after having spent about two hours I have run out of ideas. A very simple program creating a array and having a user input 10 numbers via a dialog box. Then taking those numbers and displaying them smallest to largest. It worked fine when I had the variables set as Integers, but know that I have changed everything to Double, I can't convert the user input from String to Double. I keep getting the error "Loss of precision" "Required int, found double" . All variables and the list are Double, but something is being read as an Integer somewhere, somehow. Any recommendations?


double list [] = new double [10];

for (double num = 0.0; num < list.length ; num++){
String numStr = JOptionPane.showInputDialog("Enter a number");
list [num] = Double.parseDouble(numStr);
}

Arrays.sort(list);
for (double x = 0.0; x < list.length; x++){
}

final String numbersList = Arrays.toString( list );
JOptionPane.showMessageDialog( null, "Your numbers are: " + numbersList );
}
}

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It's not clear why you'd be getting that error with the code you've posted. It's also not clear why you changed every int to a double, especially those used as for loop control variables which are then used as array indices. doubles cannot be used as array indices, so that IS a real error you should be getting.

Thanks. I changed the for loop control variables back to Integers and it works now. Don't really understand why that caused the "list [num] = Double.parseDouble(numStr);" line to highlight as an error though, but the important thing is it works now. Thanks again.

Originally Posted by suteki73

Thanks. I changed the for loop control variables back to Integers and it works now. Don't really understand why that caused the "list [num] = Double.parseDouble(numStr);" line to highlight as an error though

Think about it this way:
If the variable num is a double, then:
num = 1.3;
list[num]
exactly what index is 1.3?
That is why it must be an int and not a double