Thread: java parser

I changed the code in this way to use split method instead of StringTokenizer

public class Parser {
	public static void main(String args[]){
 
		parser("There are 5 table (dimension: 4 in 5 in 3 meters) in the room.");
 
 
	}
 
	public static void parser(String str){
 
		String type = new String("Type: ");
		String number = new String("Numbers: ");
		String size = new String("Size: ");
		String position = new String("Position: ");
 
		String[] tokens = str.split(" ");
if(str.equals("is")){
			System.out.println(number + "1");
 
		}
		else{
			System.out.println(number + tokens[2]);
		}
 
 
		}
	}

It works What is your opinion?
(And thank you for that point about StringTokenizer)

I want to say that if the token equals to the, print the next token as position. How can I say this? Using split.

for example: "There are 5 tables (dimension: 4 in 5 in 3 meters) in the room."
the position is this part: "in the room" and I want to say that:

if(tokens.equals("the")){
			System.out.println(position + tokens.nextToken);
		}

Here "tokens" is the array of strings that contains the tokens of the str sentence(the original sentence) that have been tokenized by split method. I want to say that if one of these tokens is equals to "the" then print out the next token ( which is the position. here: room). but I really don't know what I should use to accomplish this
This question that we are discussing about is the first part of an Assignment that consists of 3 parts and the due time is tomorrow night I'm really sad and disappointed

for(int i= 0; i < tokens.length; i++){
 
			if(tokens[i] == "the"){
				System.out.println(tokens[i+1]);
			}

I did this but It doesn't work. It doesn't throw exception and doesn't have any errors, but It also gives no result
I set a loop to look through the array and find the "the" and then prints the next array element. What's wrong with it?

for(int i= 0; i < tokens.length; i++){
 
			if(tokens[i].equals("the")){
				System.out.println(tokens[i+1]);
			}

I changed it and it worked Thank you

In some cases, there are more than just one word after the word "the" that declare the position. for example:
"There are 5 tables (dimension: 4 in 5 in 3 meters) in the Mike's room." Now I want to say that, when you find the "the" then print out all of the words after that. I used this but it throws exception

for(int i= 0; i < tokens.length; i++){
 
			if(tokens[i].equals("the")){
				while(strTok.hasMoreTokens()){
					System.out.println(tokens[i++]);
				}
			}
		}

.

There is also something else for example when the parser finds the wanted word ( e.g it's the position (room) ) then I want to print it in this way:
Position: Room
I mean I want the first letter to be Uppercase. How can I do this?

--- Update ---

Originally Posted by javaiscool

I would searc for the word immediagely after "there is a" and throw that into a variable, then grab the numbers of the dimensions and multiply them then print it all

It sounds a good idea, Thank you . But now I'm talking about the Position which is always after the word "the". I want to search for the "the" and print the words after that which is the position (in this example: Milke's room)

for(int i= 0; i < tokens.length; i++){
 
			if(tokens[i].equals("the")){
				System.out.println(tokens[i+1]);
			}

Here I accomplished this but it won't work for all examples. For instance if there would be more than just one word for the position ( Mike's room) then it will print just "Mike's" and this is not the Position! So I want to say that when you find the "the" PLEEEEEASE :d while this sentence has words, print all of them

Thank you And I also want to remove the plural s in the word. For example to make the word "tables" into "Table".

import java.util.ArrayList;
import java.util.StringTokenizer;
 
//import java.util.StringTokenizer;
 
    public class Parser {
 
	public static void main(String args[]){
 
		parser("There are twenty two tables (dimension: 4 in 5 in 3 meters) in the Arash's room.");
 
	}
 
	public static void parser(String str){
 
		//Declaring the basic strings to be printed out in the console;
 
		String type = new String("Type: ");
		String number = new String("Numbers: ");
		String size = new String("Size: ");
		String position = new String("Position: ");
 
		//parsing the str String by split method;
 
		String[] tokens = str.split(" ");
 
		//Getting the Type of the object;
 
		int counter = 0;
				for(int i = 1; i < tokens.length; i++){
 
					if(tokens[i].contains("(")){
 
						counter = i;
						break;
 
					}
 
				}
 
 
				System.out.println(type + tokens[counter - 1].substring(0,1).toUpperCase().concat(tokens[counter -1].substring(counter)) );
 
				 //Getting the number of the object;
				if(str.substring(6,8).equalsIgnoreCase("is")){
					System.out.println(number + "1");
				}
					else{
						int counter1 = 0;
						for(int i = 1; i < tokens.length; i++){
							if(tokens[i].contains("are")){
								counter1 = i;
								break;
							}
						}
						System.out.println(number + tokens[counter1 + 1]);
					}
 
				//Getting the the size of the object;
				int counter2 = 0;
				for(int i = 1; i< tokens.length; i++){
					if(tokens[i].contains("(dimension")){
						counter2 = i;
						break;
					}
 
				}
				ArrayList<Character> chars = new ArrayList<>();
				for( int j = counter2; j < tokens.length;j++){
					if(Character.isDigit(tokens[j].toCharArray()[0])){
						chars.add(tokens[j].toCharArray()[0]);
					}
 
				}
				int lent = chars.size();
				if(lent == 3){
 
					double one = Integer.parseInt(a);
					System.out.println(one);
				}
 
				}
 
	}

Here is the code I wrote today. There's a problem with the part about size:

 
				//Getting the the size of the object;
				int counter2 = 0;
				for(int i = 1; i< tokens.length; i++){
					if(tokens[i].contains("(dimension")){
						counter2 = i;
						break;
					}
 
				}
				ArrayList<Character> chars = new ArrayList<>();
				for( int j = counter2; j < tokens.length;j++){
					if(Character.isDigit(tokens[j].toCharArray()[0])){
						chars.add(tokens[j].toCharArray()[0]);
					}
 
				}
				int lent = chars.size();
				if(lent == 3){
 
					double one = Integer.parseInt(a);
					System.out.println(one);
				}
 
				}

I said if there was this token "(dimension" in the array named token, then take the index and after that, look for a digit and put the digits in an arraylist named "chars". Now, I don't know how to access each value of the arraylist so i can multiple them and calculate the size. I want to access to chars[0], chars[1] and chars[3]. Could you please help me with this?
Thanks in advance

int lent = chars.size();
				if(lent == 3){
				int one = chars.get(2);
				System.out.println(one);
				}
 
				}

I did this, but it doesn't work
The size of the arraylist is 3 and it's value is [4,5,3] but when I attempt to reach its elements by .get() method, it prints out 52, 53 and 51 What's wrong with this?

Again, Hello

I want to know how can I say that search the whole tokens[] Array and if you find the token containing "the" then print the next tokens till it was all finished.

int counter3 = 0;
					for(int i = 0; i< tokens.length; i++){
						if(tokens[i].contains("the")){
							counter3 = i+1;
							break;	
						}
					}
					ArrayList<String> newTokens = new ArrayList<>();
					for( int k = counter3; k < tokens.length; k++){
						newTokens.add(tokens[k]);
						}
					int index = newTokens.indexOf(".");
					String position1 = newTokens.get(index);
					System.out.println(position1);

Here, I told it to look for the token that contains "the" and I set the counter to the next index of that token that contains "the". Then I broke the for loop and constructed an ArrayList and put all the tokens in that ArrayList named newTokens. Then I tried to get the index of the token that contains "." and print the String in it using .get() method. But it throws an exception. What's wrong with it?
Thank you so much for all your helps

--- Update ---

I guess I made a mistake here and it won't give the result that I want because even if it finds the index and prints the token, the output will be this:
room.

If we print the newTokens arrayList, the output will be this:
[Mike's, room.]
How can I print its elements in a way that the output would be like this:

Mike's room.

Here is the error message:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: -1
	at java.util.ArrayList.elementData(Unknown Source)
	at java.util.ArrayList.get(Unknown Source)
	at org.bihe.parser.parser(parser.java:137)
	at org.bihe.parser.main(parser.java:10)

--- Update ---

Originally Posted by Norm

use a loop and the System.out.print() method to put the String on the same line as the last call to print()
Use a call to println() to have the next output moved to the next line.

I did not understand this part Would you please explain it more?