Thread: Create a java program to determine what integers of two, three, and four digits are equal to the sum of the cubes of their digits?

import java.util.*;
import java.io.*;
 
class Cubesum {
	public static void main(String args[]){
		int input=0;
		int num1,num2,num3;
 
		//read the number
		System.out.print("Enter a positive integer: ");
		Scanner console = new Scanner(System.in);
		input= Integer.parseInt(console.nextLine());
 
		int number = input; //number is a temp variable
		int counter = 0; //counter is used to count no of digits
 
		while(number>0){
			int t= number%10;
			counter += t * t * t;
			number = number/10;
		}
		System.out.println("The sum of the cubes of the digits is: "+counter);
 
	}
}

Output:
Enter a positive integer: 223
The sum of the cubes of the digits is: 43

I want to get this output from the program:
371 = 3³+7³+1³
How would I do it?

You have the wrong formula.
Hint: you need to use the math class.
Another hint: Math.pow(num1, 3) //example

Formula is quite all right. This code sample calculates sum of cubes of digits for a single number.

Now you need simply enclose this calculation in a loop which iterates "number" from 10 to 9999 and print only those numbers for which "counter" equals to "number".